Orthogonality loss — where it appears
Named by 2 essays across 2 fields — each of them below, with the objects they name alongside it.
Doing it twice
Cholesky QR squares the condition number — a fitted slope of 1.95 in κ against the Householder sweep's 1.00. Run the identical routine a second time on the Q it returned and the slope is 0.93, the orthogonality is at or below the sweep's at every κ, and the price is one more all-reduce.
One sequence and two recurrences
CGLS and LSQR compute the same iterates — the minimiser over a space is unique, so there is nothing to choose between them in the algebra. At κ = 10⁶ they cost 42 steps and 47. At κ = 10¹⁰ they cost 110 and 209, across four seeds, and the quantity that separates them is the orthogonality of a basis neither of them keeps.
Named alongside it
The objects these essays reach for when they reach for this one.
Normal equationsUnit roundoffAll reduceBackward stabilityCglsCholesky qrCommunication avoidingCondition numberForward errorGolub kahan bidiagonalisationGram matrixKrylov subspace