The augmented step's two condition numbers, and the one the error obeys
At its defaults it draws the augmented step's two condition numbers, and the one the error obeys. κ₂ is a worst case over all perturbations of the same NORM, and a normwise perturbation is allowed to put its whole budget on the smallest entry of a matrix. The componentwise number — Skeel's ‖ |A⁻¹||A||x| ‖ / ‖x‖ — is a worst case over perturbations proportional to the entries, which is what a backward-stable factorisation actually makes. For the augmented interior-point matrix the two are 3.044·10¹³ and 13.25 at μ = 10⁻¹², a ratio of 2.296·10¹², and the measured error is 9.434·10⁻¹⁶ — which is the second number times the unit roundoff and has nothing to do with the first. The componentwise line is still finding its level down to about μ = 10⁻⁴, where the two groups of constraints have not yet separated, and from there it does not move in the fourth digit; where it settles — 13.25 here — is set by how many constraints are active rather than by μ. Eliminating the second block to reach the condensed form destroys the distinction: there the componentwise number is 1.324·10¹⁴, tracking the normwise one, because the large entries have been summed into CᵀDC and are no longer separately identifiable.
barrier-skeel is one function in lib/figures/barrier.js —
the barrier — a condition number sent to infinity on purpose, and the number that describes the error. Everything below came out of it during this build, at
arguments taken from the essays rather than invented for this page. A figure here is the
figure a reader meets in an essay, and if the generator changes, this page changes with it.
At its defaults
Drawn even though every essay passes arguments — which on this site is every essay, at 100% of placements since the standard pass. A default nothing exercises is a trap for the next essay to call this with none, and this is the page where a default that has drifted from the figures around it becomes visible.
κ₂ is a worst case over all perturbations of the same NORM, and a normwise perturbation is allowed to put its whole budget on the smallest entry of a matrix. The componentwise number — Skeel's ‖ |A⁻¹||A||x| ‖ / ‖x‖ — is a worst case over perturbations proportional to the entries, which is what a backward-stable factorisation actually makes. For the augmented interior-point matrix the two are 3.044·10¹³ and 13.25 at μ = 10⁻¹², a ratio of 2.296·10¹², and the measured error is 9.434·10⁻¹⁶ — which is the second number times the unit roundoff and has nothing to do with the first. The componentwise line is still finding its level down to about μ = 10⁻⁴, where the two groups of constraints have not yet separated, and from there it does not move in the fourth digit; where it settles — 13.25 here — is set by how many constraints are active rather than by μ. Eliminating the second block to reach the condensed form destroys the distinction: there the componentwise number is 1.324·10¹⁴, tracking the normwise one, because the large entries have been summed into CᵀDC and are no longer separately identifiable.
p: 6
The arguments are the ones A condition number sent to infinity passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
κ₂ is a worst case over all perturbations of the same NORM, and a normwise perturbation is allowed to put its whole budget on the smallest entry of a matrix. The componentwise number — Skeel's ‖ |A⁻¹||A||x| ‖ / ‖x‖ — is a worst case over perturbations proportional to the entries, which is what a backward-stable factorisation actually makes. For the augmented interior-point matrix the two are 3.044·10¹³ and 13.25 at μ = 10⁻¹², a ratio of 2.296·10¹², and the measured error is 9.434·10⁻¹⁶ — which is the second number times the unit roundoff and has nothing to do with the first. The componentwise line is still finding its level down to about μ = 10⁻⁴, where the two groups of constraints have not yet separated, and from there it does not move in the fourth digit; where it settles — 13.25 here — is set by how many constraints are active rather than by μ. Eliminating the second block to reach the condensed form destroys the distinction: there the componentwise number is 1.324·10¹⁴, tracking the normwise one, because the large entries have been summed into CᵀDC and are no longer separately identifiable.
p: 10
The arguments are the ones Two condition numbers of one matrix passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
κ₂ is a worst case over all perturbations of the same NORM, and a normwise perturbation is allowed to put its whole budget on the smallest entry of a matrix. The componentwise number — Skeel's ‖ |A⁻¹||A||x| ‖ / ‖x‖ — is a worst case over perturbations proportional to the entries, which is what a backward-stable factorisation actually makes. For the augmented interior-point matrix the two are 2.52·10¹³ and 11.19 at μ = 10⁻¹², a ratio of 2.252·10¹², and the measured error is 6.091·10⁻¹⁶ — which is the second number times the unit roundoff and has nothing to do with the first. The componentwise line is still finding its level down to about μ = 10⁻⁴, where the two groups of constraints have not yet separated, and from there it does not move in the fourth digit; where it settles — 11.19 here — is set by how many constraints are active rather than by μ. Eliminating the second block to reach the condensed form destroys the distinction: there the componentwise number is 2.759·10¹⁴, tracking the normwise one, because the large entries have been summed into CᵀDC and are no longer separately identifiable.
p: 4
The arguments are the ones Two condition numbers of one matrix passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
κ₂ is a worst case over all perturbations of the same NORM, and a normwise perturbation is allowed to put its whole budget on the smallest entry of a matrix. The componentwise number — Skeel's ‖ |A⁻¹||A||x| ‖ / ‖x‖ — is a worst case over perturbations proportional to the entries, which is what a backward-stable factorisation actually makes. For the augmented interior-point matrix the two are 1.063·10¹³ and 11.09 at μ = 10⁻¹², a ratio of 9.585·10¹¹, and the measured error is 8.739·10⁻¹⁶ — which is the second number times the unit roundoff and has nothing to do with the first. The componentwise line is still finding its level down to about μ = 10⁻⁴, where the two groups of constraints have not yet separated, and from there it does not move in the fourth digit; where it settles — 11.09 here — is set by how many constraints are active rather than by μ. Eliminating the second block to reach the condensed form destroys the distinction: there the componentwise number is 1.803·10¹⁴, tracking the normwise one, because the large entries have been summed into CᵀDC and are no longer separately identifiable.
p: 5
The arguments are the ones Two condition numbers of one matrix passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
κ₂ is a worst case over all perturbations of the same NORM, and a normwise perturbation is allowed to put its whole budget on the smallest entry of a matrix. The componentwise number — Skeel's ‖ |A⁻¹||A||x| ‖ / ‖x‖ — is a worst case over perturbations proportional to the entries, which is what a backward-stable factorisation actually makes. For the augmented interior-point matrix the two are 1.822·10¹³ and 15.57 at μ = 10⁻¹², a ratio of 1.17·10¹², and the measured error is 6.124·10⁻¹⁶ — which is the second number times the unit roundoff and has nothing to do with the first. The componentwise line is still finding its level down to about μ = 10⁻⁴, where the two groups of constraints have not yet separated, and from there it does not move in the fourth digit; where it settles — 15.57 here — is set by how many constraints are active rather than by μ. Eliminating the second block to reach the condensed form destroys the distinction: there the componentwise number is 4.19·10¹⁴, tracking the normwise one, because the large entries have been summed into CᵀDC and are no longer separately identifiable.
n: 4, p: 6
The arguments are the ones Two condition numbers of one matrix passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
κ₂ is a worst case over all perturbations of the same NORM, and a normwise perturbation is allowed to put its whole budget on the smallest entry of a matrix. The componentwise number — Skeel's ‖ |A⁻¹||A||x| ‖ / ‖x‖ — is a worst case over perturbations proportional to the entries, which is what a backward-stable factorisation actually makes. For the augmented interior-point matrix the two are 5.37·10¹² and 11.34 at μ = 10⁻¹², a ratio of 4.737·10¹¹, and the measured error is 4.243·10⁻¹⁶ — which is the second number times the unit roundoff and has nothing to do with the first. The componentwise line is still finding its level down to about μ = 10⁻⁴, where the two groups of constraints have not yet separated, and from there it does not move in the fourth digit; where it settles — 11.34 here — is set by how many constraints are active rather than by μ. Eliminating the second block to reach the condensed form destroys the distinction: there the componentwise number is 2.414·10¹³, tracking the normwise one, because the large entries have been summed into CᵀDC and are no longer separately identifiable.
What it checked while drawing
Every figure above checked its own claims on the way to being drawn, and a claim that failed
would have stopped the picture rather than shipped a wrong one. Those checks used to leave
no trace at all: a passing one returned true and the only evidence the figure had
checked anything was that nothing crashed. The list below is what they actually said, collected
by running this generator with an observer installed — not a description of
what it is believed to check.
11 distinct claims across 6 sets of arguments, grouped below by shape — because most of them are one sentence with a different number in it, and how many separate times that sentence was put to the test is the informative part.
a factorisation that did not break down
a finite double, since an infinity is not a rational
a pivot rule this routine implements
a problem with constraints and unknowns
a size the exact rational solve can afford
an active set that is neither empty nor everything
and it is a two-figure number at every μ
LU is for square matrices
matmul shapes agree
the componentwise number settles and then does not move
while the normwise one is twelve orders larger
Against the rule
It draws a decomposition and prints its residual. It calls
barrierSweep,
and every figure above carries the badge — which residualcheck verifies by looking
for it in the emitted SVG rather than by finding the call that builds one. A badge that is
constructed and then left out of the body is the failure that check exists for.
Across the library: the rule bites on 217
of 397 generators —
199 print a residual and
18 are exempt with a published reason;
180 factorise nothing.
Read from lib/residual-rule.js, which is the same body the gate enforces from,
and the gate's last check fails the build if this page and it disagree about any generator.
Where it is called
Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.
A condition number sent to infinity
An interior-point method manufactures an ill-conditioned matrix on every iteration, deliberately, because the separating of a diagonal is how it discovers which constraints are active. Written one way the answer keeps fifteen digits at a condition number of 3·10¹⁵. Written the other way — the way almost every code writes it — it has none left.
Two errors, and whose fault they areTwo condition numbers of one matrix
κ₂ is a worst case over perturbations of a given norm, and a normwise perturbation may put its whole budget on the smallest entry. The componentwise number is a worst case over perturbations proportional to the entries, which is what a backward-stable factorisation actually makes. On one matrix they are 3·10¹³ and 13.3, and the error obeys the second.