The Krawczyk operator on a box of half-width 0.4
At its defaults it draws the krawczyk operator on a box of half-width 0.4. Two rectangles in the plane. The outer one is the box handed in; the inner one is K(X), the image the operator returns; and the marked point is the root (√2, √2), known in closed form. The image is narrower than the box — 0.2263 against 0.8 — and the verdict is: exactly one root.
box-verdict is one function in lib/figures/krawczyk.js —
verdicts — exactly one root in this box, or none, or nothing can be said. Everything below came out of it during this build, at
arguments taken from the essays rather than invented for this page. A figure here is the
figure a reader meets in an essay, and if the generator changes, this page changes with it.
At its defaults
Drawn even though every essay passes arguments — which on this site is every essay, at 100% of placements since the standard pass. A default nothing exercises is a trap for the next essay to call this with none, and this is the page where a default that has drifted from the figures around it becomes visible.
Two rectangles in the plane. The outer one is the box handed in; the inner one is K(X), the image the operator returns; and the marked point is the root (√2, √2), known in closed form. The image is narrower than the box — 0.2263 against 0.8 — and the verdict is: exactly one root.
radius: 0.4
The arguments are the ones Proving the answer is in the box passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
Two rectangles in the plane. The outer one is the box handed in; the inner one is K(X), the image the operator returns; and the marked point is the root (√2, √2), known in closed form. The image is narrower than the box — 0.2263 against 0.8 — and the verdict is: exactly one root.
radius: 0.02
The arguments are the ones Proving the answer is in the box passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
Two rectangles in the plane. The outer one is the box handed in; the inner one is K(X), the image the operator returns; and the marked point is the root (√2, √2), known in closed form. The image is narrower than the box — 0.0005657 against 0.04 — and the verdict is: no root at all.
radius: 0.05
The arguments are the ones Proving the answer is in the box passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
Two rectangles in the plane. The outer one is the box handed in; the inner one is K(X), the image the operator returns; and the marked point is the root (√2, √2), known in closed form. The image is narrower than the box — 0.003536 against 0.1 — and the verdict is: no conclusion.
radius: 0.1
The arguments are the ones Proving the answer is in the box passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
Two rectangles in the plane. The outer one is the box handed in; the inner one is K(X), the image the operator returns; and the marked point is the root (√2, √2), known in closed form. The image is narrower than the box — 0.01414 against 0.2 — and the verdict is: exactly one root.
radius: 1.4
The arguments are the ones Proving the answer is in the box passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
Two rectangles in the plane. The outer one is the box handed in; the inner one is K(X), the image the operator returns; and the marked point is the root (√2, √2), known in closed form. The image is narrower than the box — 2.772 against 2.8 — and the verdict is: no conclusion.
What it checked while drawing
Every figure above checked its own claims on the way to being drawn, and a claim that failed
would have stopped the picture rather than shipped a wrong one. Those checks used to leave
no trace at all: a passing one returned true and the only evidence the figure had
checked anything was that nothing crashed. The list below is what they actually said, collected
by running this generator with an observer installed — not a description of
what it is believed to check.
6 distinct claims across 6 sets of arguments, grouped below by shape — because most of them are one sentence with a different number in it, and how many separate times that sentence was put to the test is the informative part.
a box proved empty does not contain the root
a box the operator can be evaluated on
a precision the arithmetic can round outward at
a verified box contains the exactly known root
and its image is strictly inside it
LU is for square matrices
Against the rule
The rule does not apply to it. It factorises nothing, so there is no residual it could be withholding. That is worth stating rather than leaving blank: a site that reported the rule as satisfied by every generator would be counting mostly generators the rule never reached.
Across the library: the rule bites on 217
of 397 generators —
199 print a residual and
18 are exempt with a published reason;
180 factorise nothing.
Read from lib/residual-rule.js, which is the same body the gate enforces from,
and the gate's last check fails the build if this page and it disagree about any generator.
Where it is called
Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.
Proving the answer is in the box
Every other method here computes a number and estimates how wrong it is. This one returns a verdict: there is exactly one solution in this box, or there is none, or — the honest third outcome — nothing can be said. Two of the three are proofs about infinitely many points from finitely many operations.
The arithmetic underneathWhere the box is cut
A branch-and-bound with an interval operator settles a whole square — two roots proved unique, forty-two regions proved empty, nothing left undecided, in 87 evaluations. Move the roots so one lands on the first bisection and it proves nothing at all, at any depth. Cutting at 0.485 instead of 0.5 finds both, in a quarter of the work.