Generator

contour-recovery

One function in the beyn library, called 8 times across 3 essays. Below: what it draws at its defaults, what it draws at every value an essay asks for, the 10 claims it put to the test while drawing them, and where it stands against the rule this site is named for.

At its defaults it draws 4 eigenvalues inside a circle of radius 4, and 2 moments to reach them. A delay eigenvalue problem T(λ) = A − λI + e^{−λ}I, which has infinitely many eigenvalues and no linearisation, so the only finite question is what lies inside a given contour. The crosses are the Lambert-W closed form λ = μ + W_k(γe^{−μ}), one per eigenvalue of A per branch; the discs are what 2 contour moments against a probe block of 2 recover, agreeing to 2.16·10⁻¹². With one moment the method could have returned at most 2 of them and would have said nothing about the rest.

contour-recovery is one function in lib/figures/beyn.js — a ceiling with a knob on it — higher contour moments, and the conditioning that rises with them. Everything below came out of it during this build, at arguments taken from the essays rather than invented for this page. A figure here is the figure a reader meets in an essay, and if the generator changes, this page changes with it.

At its defaults

Drawn even though every essay passes arguments — which on this site is every essay, at 100% of placements since the standard pass. A default nothing exercises is a trap for the next essay to call this with none, and this is the page where a default that has drifted from the figures around it becomes visible.

4 eigenvalues inside a circle of radius 4, and 2 moments to reach themA delay eigenvalue problem T(λ) = A − λI + e^{−λ}I, which has infinitely many eigenvalues and no linearisation, so the only finite question is what lies inside a given contour. The crosses are the Lambert-W closed form λ = μ + W_k(γe^{−μ}), one per eigenvalue of A per branch; the discs are what 2 contour moments against a probe block of 2 recover, agreeing to 2.16·10⁻¹². With one moment the method could have returned at most 2 of them and would have said nothing about the rest.-4-3-2-101234-4-3-2-101234real partimaginary partan infinite spectrum, finitely askedinside the contour4probes2moments used2values returned8worst against the closed form2.2·10⁻¹²infinitely many eigenvaluesand a question with an answer

A delay eigenvalue problem T(λ) = A − λI + e^{−λ}I, which has infinitely many eigenvalues and no linearisation, so the only finite question is what lies inside a given contour. The crosses are the Lambert-W closed form λ = μ + W_k(γe^{−μ}), one per eigenvalue of A per branch; the discs are what 2 contour moments against a probe block of 2 recover, agreeing to 2.16·10⁻¹². With one moment the method could have returned at most 2 of them and would have said nothing about the rest.

radius: 4

The arguments are the ones A ceiling with a knob on it passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

4 eigenvalues inside a circle of radius 4, and 2 moments to reach themA delay eigenvalue problem T(λ) = A − λI + e^{−λ}I, which has infinitely many eigenvalues and no linearisation, so the only finite question is what lies inside a given contour. The crosses are the Lambert-W closed form λ = μ + W_k(γe^{−μ}), one per eigenvalue of A per branch; the discs are what 2 contour moments against a probe block of 2 recover, agreeing to 2.16·10⁻¹². With one moment the method could have returned at most 2 of them and would have said nothing about the rest.-4-3-2-101234-4-3-2-101234real partimaginary partan infinite spectrum, finitely askedinside the contour4probes2moments used2values returned8worst against the closed form2.2·10⁻¹²infinitely many eigenvaluesand a question with an answer

A delay eigenvalue problem T(λ) = A − λI + e^{−λ}I, which has infinitely many eigenvalues and no linearisation, so the only finite question is what lies inside a given contour. The crosses are the Lambert-W closed form λ = μ + W_k(γe^{−μ}), one per eigenvalue of A per branch; the discs are what 2 contour moments against a probe block of 2 recover, agreeing to 2.16·10⁻¹². With one moment the method could have returned at most 2 of them and would have said nothing about the rest.

radius: 2

The arguments are the ones A ceiling with a knob on it passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

2 eigenvalues inside a circle of radius 2, and 1 moments to reach themA delay eigenvalue problem T(λ) = A − λI + e^{−λ}I, which has infinitely many eigenvalues and no linearisation, so the only finite question is what lies inside a given contour. The crosses are the Lambert-W closed form λ = μ + W_k(γe^{−μ}), one per eigenvalue of A per branch; the discs are what 1 contour moment against a probe block of 2 recover, agreeing to 2.44·10⁻¹⁵. With one moment the method could have returned at most 2 of them and would have said nothing about the rest.-2-1012-2-1012real partimaginary partan infinite spectrum, finitely askedinside the contour2probes2moments used1values returned4worst against the closed form2.4·10⁻¹⁵infinitely many eigenvaluesand a question with an answer

A delay eigenvalue problem T(λ) = A − λI + e^{−λ}I, which has infinitely many eigenvalues and no linearisation, so the only finite question is what lies inside a given contour. The crosses are the Lambert-W closed form λ = μ + W_k(γe^{−μ}), one per eigenvalue of A per branch; the discs are what 1 contour moment against a probe block of 2 recover, agreeing to 2.44·10⁻¹⁵. With one moment the method could have returned at most 2 of them and would have said nothing about the rest.

radius: 3

The arguments are the ones A ceiling with a knob on it passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

3 eigenvalues inside a circle of radius 3, and 2 moments to reach themA delay eigenvalue problem T(λ) = A − λI + e^{−λ}I, which has infinitely many eigenvalues and no linearisation, so the only finite question is what lies inside a given contour. The crosses are the Lambert-W closed form λ = μ + W_k(γe^{−μ}), one per eigenvalue of A per branch; the discs are what 2 contour moments against a probe block of 2 recover, agreeing to 7.11·10⁻¹⁵. With one moment the method could have returned at most 2 of them and would have said nothing about the rest.-3-2-10123-3-2-10123real partimaginary partan infinite spectrum, finitely askedinside the contour3probes2moments used2values returned6worst against the closed form7.1·10⁻¹⁵infinitely many eigenvaluesand a question with an answer

A delay eigenvalue problem T(λ) = A − λI + e^{−λ}I, which has infinitely many eigenvalues and no linearisation, so the only finite question is what lies inside a given contour. The crosses are the Lambert-W closed form λ = μ + W_k(γe^{−μ}), one per eigenvalue of A per branch; the discs are what 2 contour moments against a probe block of 2 recover, agreeing to 7.11·10⁻¹⁵. With one moment the method could have returned at most 2 of them and would have said nothing about the rest.

radius: 5

The arguments are the ones A ceiling with a knob on it passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

12 eigenvalues inside a circle of radius 5, and 6 moments to reach themA delay eigenvalue problem T(λ) = A − λI + e^{−λ}I, which has infinitely many eigenvalues and no linearisation, so the only finite question is what lies inside a given contour. The crosses are the Lambert-W closed form λ = μ + W_k(γe^{−μ}), one per eigenvalue of A per branch; the discs are what 6 contour moments against a probe block of 2 recover, agreeing to 5.02·10⁻¹⁴. With one moment the method could have returned at most 2 of them and would have said nothing about the rest.-6-4-20246-6-4-20246real partimaginary partan infinite spectrum, finitely askedinside the contour12probes2moments used6values returned24worst against the closed form5·10⁻¹⁴infinitely many eigenvaluesand a question with an answer

A delay eigenvalue problem T(λ) = A − λI + e^{−λ}I, which has infinitely many eigenvalues and no linearisation, so the only finite question is what lies inside a given contour. The crosses are the Lambert-W closed form λ = μ + W_k(γe^{−μ}), one per eigenvalue of A per branch; the discs are what 6 contour moments against a probe block of 2 recover, agreeing to 5.02·10⁻¹⁴. With one moment the method could have returned at most 2 of them and would have said nothing about the rest.

radius: 6

The arguments are the ones A ceiling with a knob on it passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

12 eigenvalues inside a circle of radius 6, and 6 moments to reach themA delay eigenvalue problem T(λ) = A − λI + e^{−λ}I, which has infinitely many eigenvalues and no linearisation, so the only finite question is what lies inside a given contour. The crosses are the Lambert-W closed form λ = μ + W_k(γe^{−μ}), one per eigenvalue of A per branch; the discs are what 6 contour moments against a probe block of 2 recover, agreeing to 4.22·10⁻¹³. With one moment the method could have returned at most 2 of them and would have said nothing about the rest.-7-5-3-11357-7-5-3-11357real partimaginary partan infinite spectrum, finitely askedinside the contour12probes2moments used6values returned24worst against the closed form4.2·10⁻¹³infinitely many eigenvaluesand a question with an answer

A delay eigenvalue problem T(λ) = A − λI + e^{−λ}I, which has infinitely many eigenvalues and no linearisation, so the only finite question is what lies inside a given contour. The crosses are the Lambert-W closed form λ = μ + W_k(γe^{−μ}), one per eigenvalue of A per branch; the discs are what 6 contour moments against a probe block of 2 recover, agreeing to 4.22·10⁻¹³. With one moment the method could have returned at most 2 of them and would have said nothing about the rest.

What it checked while drawing

Every figure above asserted its own claims on the way to being drawn, and a claim that failed would have failed the build rather than drawn a wrong picture. Those assertions used to leave no trace at all: a passing one returned true and the only evidence the figure had checked anything was that nothing crashed. The list below is what they actually said, collected by running this generator with an observer installed — not a description of what it is believed to check.

10 distinct claims across 6 sets of arguments, grouped below by shape — because most of them are one sentence with a different number in it, and how many separate times that sentence was put to the test is the informative part.

a contour the closed form covers

a contour with something inside it

a division by a complex number that is not zero

a Lambert argument that is not zero

a probe block the contour can afford

a size the contour integrals can afford

enough moments for the block asked for

every eigenvalue inside the contour is found

LU is for square matrices

matmul shapes agree

Against the rule

It draws a decomposition and prints its residual. It calls contourMoments, momentEigenvalues, and every figure above carries the badge — which residualcheck verifies by looking for it in the emitted SVG rather than by finding the call that builds one. A badge that is constructed and then left out of the body is the failure that check exists for.

Across the library: the rule bites on 192 of 346 generators — 174 print a residual and 18 are exempt with a published reason; 154 factorise nothing. Read from lib/residual-rule.js, which is the same body the gate enforces from, and the gate's last check fails the build if this page and it disagree about any generator.

Where it is called

Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.

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