The curvature pᵀAp/pᵀp along conjugate gradients on a matrix with one eigenvalue at −10^-1
At its defaults it draws the curvature pᵀap/pᵀp along conjugate gradients on a matrix with one eigenvalue at −10^-1. The matrix is 40×40, positive definite apart from a single eigenvalue at -0.1. Conjugate gradients divides by pᵀAp at every step, and the quantity runs 5.43, 2.72, 1.71, 0.687 before turning negative at step 6, where it is -0.02656. That direction is a proof: one matrix–vector product from outside the iteration confirms it, and it recovers 26.6 per cent of the eigenvalue. MINRES on the same system never forms this quantity, meets nothing, and returns the solution in 37 steps.
curvature-trail is one function in lib/figures/curvature.js —
negative curvature — the division that cannot be done, as an output. Everything below came out of it during this build, at
arguments taken from the essays rather than invented for this page. A figure here is the
figure a reader meets in an essay, and if the generator changes, this page changes with it.
At its defaults
Drawn even though every essay passes arguments — which on this site is every essay, at 100% of placements since the standard pass. A default nothing exercises is a trap for the next essay to call this with none, and this is the page where a default that has drifted from the figures around it becomes visible.
The matrix is 40×40, positive definite apart from a single eigenvalue at -0.1. Conjugate gradients divides by pᵀAp at every step, and the quantity runs 5.43, 2.72, 1.71, 0.687 before turning negative at step 6, where it is -0.02656. That direction is a proof: one matrix–vector product from outside the iteration confirms it, and it recovers 26.6 per cent of the eigenvalue. MINRES on the same system never forms this quantity, meets nothing, and returns the solution in 37 steps.
logLambda: 0, n: 60
The arguments are the ones A proof that does not ask how large the matrix is passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
The matrix is 60×60, positive definite apart from a single eigenvalue at -1. Conjugate gradients divides by pᵀAp at every step, and the quantity runs 6.27, 3.16, 2.21, 0.698 before turning negative at step 5, where it is -0.2437. That direction is a proof: one matrix–vector product from outside the iteration confirms it, and it recovers 24.4 per cent of the eigenvalue. MINRES on the same system never forms this quantity, meets nothing, and returns the solution in 42 steps.
logLambda: -1
The arguments are the ones The division that cannot be done passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
The matrix is 40×40, positive definite apart from a single eigenvalue at -0.1. Conjugate gradients divides by pᵀAp at every step, and the quantity runs 5.43, 2.72, 1.71, 0.687 before turning negative at step 6, where it is -0.02656. That direction is a proof: one matrix–vector product from outside the iteration confirms it, and it recovers 26.6 per cent of the eigenvalue. MINRES on the same system never forms this quantity, meets nothing, and returns the solution in 37 steps.
logLambda: -3
The arguments are the ones The division that cannot be done passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
The matrix is 40×40, positive definite apart from a single eigenvalue at -0.001. Conjugate gradients divides by pᵀAp at every step, and the quantity runs 5.44, 2.76, 1.83, 0.884 before turning negative at step 9, where it is -2.811·10⁻⁴. That direction is a proof: one matrix–vector product from outside the iteration confirms it, and it recovers 28.1 per cent of the eigenvalue. MINRES on the same system never forms this quantity, meets nothing, and returns the solution in 39 steps.
logLambda: -2
The arguments are the ones The division that cannot be done passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
The matrix is 40×40, positive definite apart from a single eigenvalue at -0.01. Conjugate gradients divides by pᵀAp at every step, and the quantity runs 5.44, 2.75, 1.81, 0.865 before turning negative at step 8, where it is -0.004188. That direction is a proof: one matrix–vector product from outside the iteration confirms it, and it recovers 41.9 per cent of the eigenvalue. MINRES on the same system never forms this quantity, meets nothing, and returns the solution in 38 steps.
logLambda: 0
The arguments are the ones The division that cannot be done passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
The matrix is 40×40, positive definite apart from a single eigenvalue at -1. Conjugate gradients divides by pᵀAp at every step, and the quantity runs 5.4, 2.36, 0.566, -0.287 before turning negative at step 4, where it is -0.2868. That direction is a proof: one matrix–vector product from outside the iteration confirms it, and it recovers 28.7 per cent of the eigenvalue. MINRES on the same system never forms this quantity, meets nothing, and returns the solution in 36 steps.
What it checked while drawing
Every figure above checked its own claims on the way to being drawn, and a claim that failed
would have stopped the picture rather than shipped a wrong one. Those checks used to leave
no trace at all: a passing one returned true and the only evidence the figure had
checked anything was that nothing crashed. The list below is what they actually said, collected
by running this generator with an observer installed — not a description of
what it is believed to check.
6 distinct claims across 6 sets of arguments, grouped below by shape — because most of them are one sentence with a different number in it, and how many separate times that sentence was put to the test is the informative part.
a negative eigenvalue inside the range the sweep covers
a power of ten rather than an exponent literal
a size the repeated products can afford
and the direction it stopped on has negative curvature
conjugate gradients meets a non-positive curvature
while MINRES, which never forms the quantity, solves the system
Against the rule
It draws a decomposition and prints its residual. It calls
cgCurvature, minres,
and every figure above carries the badge — which residualcheck verifies by looking
for it in the emitted SVG rather than by finding the call that builds one. A badge that is
constructed and then left out of the body is the failure that check exists for.
Across the library: the rule bites on 217
of 397 generators —
199 print a residual and
18 are exempt with a published reason;
180 factorise nothing.
Read from lib/residual-rule.js, which is the same body the gate enforces from,
and the gate's last check fails the build if this page and it disagree about any generator.
Where it is called
Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.
A proof that does not ask how large the matrix is
Proving a Hessian indefinite costs three matrix–vector products when the negative eigenvalue is 3 and nine to eleven when it is a thousandth, and that pair of numbers barely moves across a fourfold range in n. The factorisation that settles the same question costs a third of n³, which grows by a factor of sixty-four over the same range.
Iterating, instead of factorisingThe division that cannot be done
Conjugate gradients divides by pᵀAp at every step, and on a matrix that is not positive definite that number can be zero or negative. The guard against it has been here from the first essay and described it as a failure. In the method that made conjugate gradients famous it is the single most valuable object the iteration can produce, and it costs six matrix–vector products.