Generator

The coefficient matrix of AX + XB = C against the answer, to n = 100

One function in the sylvester library, called 6 times across 2 essays. Below: what it draws at its defaults, what it draws at every value an essay asks for, the 3 claims it put to the test while drawing them, and where it stands against the rule this site is named for.

At its defaults it draws the coefficient matrix of ax + xb = c against the answer, to n = 100. At n = 100 the unknown X has 10000 entries and the coefficient matrix of the linear map has 10⁸ — 0.80 gigabytes of doubles. Eliminating it costs 6.67·10¹¹ operations against the 6·10⁷ Bartels and Stewart's algorithm needs, a ratio of 11111. The Kronecker form is what the equation means and it is not a method.

kronecker-size is one function in lib/figures/sylvester.js — matrix equations — the n²×n² coefficient matrix nobody forms, and sep. Everything below came out of it during this build, at arguments taken from the essays rather than invented for this page. A figure here is the figure a reader meets in an essay, and if the generator changes, this page changes with it.

At its defaults

Drawn even though every essay passes arguments — which on this site is every essay, at 100% of placements since the standard pass. A default nothing exercises is a trap for the next essay to call this with none, and this is the page where a default that has drifted from the figures around it becomes visible.

The coefficient matrix of AX + XB = C against the answer, to n = 100At n = 100 the unknown X has 10000 entries and the coefficient matrix of the linear map has 10⁸ — 0.80 gigabytes of doubles. Eliminating it costs 6.67·10¹¹ operations against the 6·10⁷ Bartels and Stewart's algorithm needs, a ratio of 11111. The Kronecker form is what the equation means and it is not a method.10¹10²10¹10³10⁵10⁷10⁹10¹¹nentries, and operationsKronecker flopsits entriesBartels–Stewartentries in Xat n = 100unknowns10⁴coefficient entries10⁸gigabytes of doubles0.8flop ratio1.1·10⁴the equation is linear in Xand nobody writes down its matrix

At n = 100 the unknown X has 10000 entries and the coefficient matrix of the linear map has 10⁸ — 0.80 gigabytes of doubles. Eliminating it costs 6.67·10¹¹ operations against the 6·10⁷ Bartels and Stewart's algorithm needs, a ratio of 11111. The Kronecker form is what the equation means and it is not a method.

nMax: 100

The arguments are the ones The coarse problem is a different problem passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

The coefficient matrix of AX + XB = C against the answer, to n = 100At n = 100 the unknown X has 10000 entries and the coefficient matrix of the linear map has 10⁸ — 0.80 gigabytes of doubles. Eliminating it costs 6.67·10¹¹ operations against the 6·10⁷ Bartels and Stewart's algorithm needs, a ratio of 11111. The Kronecker form is what the equation means and it is not a method.10¹10²10¹10³10⁵10⁷10⁹10¹¹nentries, and operationsKronecker flopsits entriesBartels–Stewartentries in Xat n = 100unknowns10⁴coefficient entries10⁸gigabytes of doubles0.8flop ratio1.1·10⁴the equation is linear in Xand nobody writes down its matrix

At n = 100 the unknown X has 10000 entries and the coefficient matrix of the linear map has 10⁸ — 0.80 gigabytes of doubles. Eliminating it costs 6.67·10¹¹ operations against the 6·10⁷ Bartels and Stewart's algorithm needs, a ratio of 11111. The Kronecker form is what the equation means and it is not a method.

nMax: 20

The arguments are the ones The elimination the matrix does not need passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

The coefficient matrix of AX + XB = C against the answer, to n = 20At n = 20 the unknown X has 400 entries and the coefficient matrix of the linear map has 1.6·10⁵ — 0.00 gigabytes of doubles. Eliminating it costs 4.27·10⁷ operations against the 4.8·10⁵ Bartels and Stewart's algorithm needs, a ratio of 89. The Kronecker form is what the equation means and it is not a method.10¹10¹10³10⁵10⁷10⁹10¹¹nentries, and operationsKronecker flopsits entriesBartels–Stewartentries in Xat n = 20unknowns400coefficient entries1.6·10⁵gigabytes of doubles0.0013flop ratio89the equation is linear in Xand nobody writes down its matrix

At n = 20 the unknown X has 400 entries and the coefficient matrix of the linear map has 1.6·10⁵ — 0.00 gigabytes of doubles. Eliminating it costs 4.27·10⁷ operations against the 4.8·10⁵ Bartels and Stewart's algorithm needs, a ratio of 89. The Kronecker form is what the equation means and it is not a method.

nMax: 50

The arguments are the ones The elimination the matrix does not need passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

The coefficient matrix of AX + XB = C against the answer, to n = 50At n = 50 the unknown X has 2500 entries and the coefficient matrix of the linear map has 6.25·10⁶ — 0.05 gigabytes of doubles. Eliminating it costs 1.04·10¹⁰ operations against the 7.5·10⁶ Bartels and Stewart's algorithm needs, a ratio of 1389. The Kronecker form is what the equation means and it is not a method.10¹10¹10³10⁵10⁷10⁹10¹¹nentries, and operationsKronecker flopsits entriesBartels–Stewartentries in Xat n = 50unknowns2500coefficient entries6.3·10⁶gigabytes of doubles0.05flop ratio1389the equation is linear in Xand nobody writes down its matrix

At n = 50 the unknown X has 2500 entries and the coefficient matrix of the linear map has 6.25·10⁶ — 0.05 gigabytes of doubles. Eliminating it costs 1.04·10¹⁰ operations against the 7.5·10⁶ Bartels and Stewart's algorithm needs, a ratio of 1389. The Kronecker form is what the equation means and it is not a method.

nMax: 200

The arguments are the ones The elimination the matrix does not need passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

The coefficient matrix of AX + XB = C against the answer, to n = 200At n = 200 the unknown X has 40000 entries and the coefficient matrix of the linear map has 1.6·10⁹ — 12.80 gigabytes of doubles. Eliminating it costs 4.27·10¹³ operations against the 4.8·10⁸ Bartels and Stewart's algorithm needs, a ratio of 88889. The Kronecker form is what the equation means and it is not a method.10¹10²10¹10³10⁵10⁷10⁹10¹¹10¹³nentries, and operationsKronecker flopsits entriesBartels–Stewartentries in Xat n = 200unknowns4·10⁴coefficient entries1.6·10⁹gigabytes of doubles13flop ratio8.9·10⁴the equation is linear in Xand nobody writes down its matrix

At n = 200 the unknown X has 40000 entries and the coefficient matrix of the linear map has 1.6·10⁹ — 12.80 gigabytes of doubles. Eliminating it costs 4.27·10¹³ operations against the 4.8·10⁸ Bartels and Stewart's algorithm needs, a ratio of 88889. The Kronecker form is what the equation means and it is not a method.

nMax: 400

The arguments are the ones The elimination the matrix does not need passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

The coefficient matrix of AX + XB = C against the answer, to n = 400At n = 400 the unknown X has 160000 entries and the coefficient matrix of the linear map has 2.56·10¹⁰ — 204.80 gigabytes of doubles. Eliminating it costs 2.73·10¹⁵ operations against the 3.84·10⁹ Bartels and Stewart's algorithm needs, a ratio of 711111. The Kronecker form is what the equation means and it is not a method.10¹10²10¹10³10⁵10⁷10⁹10¹¹10¹³10¹⁵nentries, and operationsKronecker flopsits entriesBartels–Stewartentries in Xat n = 400unknowns1.6·10⁵coefficient entries2.6·10¹⁰gigabytes of doubles205flop ratio7.1·10⁵the equation is linear in Xand nobody writes down its matrix

At n = 400 the unknown X has 160000 entries and the coefficient matrix of the linear map has 2.56·10¹⁰ — 204.80 gigabytes of doubles. Eliminating it costs 2.73·10¹⁵ operations against the 3.84·10⁹ Bartels and Stewart's algorithm needs, a ratio of 711111. The Kronecker form is what the equation means and it is not a method.

What it checked while drawing

Every figure above checked its own claims on the way to being drawn, and a claim that failed would have stopped the picture rather than shipped a wrong one. Those checks used to leave no trace at all: a passing one returned true and the only evidence the figure had checked anything was that nothing crashed. The list below is what they actually said, collected by running this generator with an observer installed — not a description of what it is believed to check.

3 distinct claims across 6 sets of arguments, grouped below by shape — because most of them are one sentence with a different number in it, and how many separate times that sentence was put to the test is the informative part.

a size the cost model is meant to cover

and the arithmetic ratio is well past ten at the largest size

the coefficient matrix has n⁴ entries

Against the rule

The rule does not apply to it. It factorises nothing, so there is no residual it could be withholding. That is worth stating rather than leaving blank: a site that reported the rule as satisfied by every generator would be counting mostly generators the rule never reached.

Across the library: the rule bites on 217 of 397 generators — 199 print a residual and 18 are exempt with a published reason; 180 factorise nothing. Read from lib/residual-rule.js, which is the same body the gate enforces from, and the gate's last check fails the build if this page and it disagree about any generator.

Where it is called

Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.

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