Generator

One lattice, two bases: an orthogonality defect of 7.071 reduced to 1

One function in the integer library, called 24 times across 7 essays. Below: what it draws at its defaults, what it draws at every value an essay asks for, the 7 claims it put to the test while drawing them, and where it stands against the rule this site is named for.

At its defaults it draws one lattice, two bases: an orthogonality defect of 7.071 reduced to 1. The dots are the lattice generated by (1, 0) and (7, 1) — every one of them, out to ±4 in each coefficient. The long pair of arrows is that basis; the short pair is what LLL returns after 1 steps, in exact rational arithmetic with δ = 3/4. The two bases generate the same set of points, which is checked rather than drawn: the lattice determinant is 1 before and 1 after, and every step of the reduction is a unimodular operation, which is what makes that so. What the reduction changes is the orthogonality defect — the product of the basis vectors' lengths over the determinant — from 7.0711 to 1. One is the floor, and it is attained only by an orthogonal basis.

lattice-basis is one function in lib/figures/integer.js — exact arithmetic — no residual to print, and a cost measured in the length of the numbers. Everything below came out of it during this build, at arguments taken from the essays rather than invented for this page. A figure here is the figure a reader meets in an essay, and if the generator changes, this page changes with it.

At its defaults

Drawn even though every essay passes arguments — which on this site is every essay, at 100% of placements since the standard pass. A default nothing exercises is a trap for the next essay to call this with none, and this is the page where a default that has drifted from the figures around it becomes visible.

One lattice, two bases: an orthogonality defect of 7.071 reduced to 1The dots are the lattice generated by (1, 0) and (7, 1) — every one of them, out to ±4 in each coefficient. The long pair of arrows is that basis; the short pair is what LLL returns after 1 steps, in exact rational arithmetic with δ = 3/4. The two bases generate the same set of points, which is checked rather than drawn: the lattice determinant is 1 before and 1 after, and every step of the reduction is a unimodular operation, which is what makes that so. What the reduction changes is the orthogonality defect — the product of the basis vectors' lengths over the determinant — from 7.0711 to 1. One is the floor, and it is attained only by an orthogonal basis.the same lattice, twicewhat the reduction may not changedet, before1det, after1defect, before7.1defect, after1LLL steps1the determinant is the invariantand the defect is what is being reduced

The dots are the lattice generated by (1, 0) and (7, 1) — every one of them, out to ±4 in each coefficient. The long pair of arrows is that basis; the short pair is what LLL returns after 1 steps, in exact rational arithmetic with δ = 3/4. The two bases generate the same set of points, which is checked rather than drawn: the lattice determinant is 1 before and 1 after, and every step of the reduction is a unimodular operation, which is what makes that so. What the reduction changes is the orthogonality defect — the product of the basis vectors' lengths over the determinant — from 7.0711 to 1. One is the floor, and it is attained only by an orthogonal basis.

skew: 7

The arguments are the ones A basis that describes its lattice badly passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

One lattice, two bases: an orthogonality defect of 7.071 reduced to 1The dots are the lattice generated by (1, 0) and (7, 1) — every one of them, out to ±4 in each coefficient. The long pair of arrows is that basis; the short pair is what LLL returns after 1 steps, in exact rational arithmetic with δ = 3/4. The two bases generate the same set of points, which is checked rather than drawn: the lattice determinant is 1 before and 1 after, and every step of the reduction is a unimodular operation, which is what makes that so. What the reduction changes is the orthogonality defect — the product of the basis vectors' lengths over the determinant — from 7.0711 to 1. One is the floor, and it is attained only by an orthogonal basis.the same lattice, twicewhat the reduction may not changedet, before1det, after1defect, before7.1defect, after1LLL steps1the determinant is the invariantand the defect is what is being reduced

The dots are the lattice generated by (1, 0) and (7, 1) — every one of them, out to ±4 in each coefficient. The long pair of arrows is that basis; the short pair is what LLL returns after 1 steps, in exact rational arithmetic with δ = 3/4. The two bases generate the same set of points, which is checked rather than drawn: the lattice determinant is 1 before and 1 after, and every step of the reduction is a unimodular operation, which is what makes that so. What the reduction changes is the orthogonality defect — the product of the basis vectors' lengths over the determinant — from 7.0711 to 1. One is the floor, and it is attained only by an orthogonal basis.

skew: 40

The arguments are the ones A basis that describes its lattice badly passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

One lattice, two bases: an orthogonality defect of 40.01 reduced to 1The dots are the lattice generated by (1, 0) and (40, 1) — every one of them, out to ±4 in each coefficient. The long pair of arrows is that basis; the short pair is what LLL returns after 1 steps, in exact rational arithmetic with δ = 3/4. The two bases generate the same set of points, which is checked rather than drawn: the lattice determinant is 1 before and 1 after, and every step of the reduction is a unimodular operation, which is what makes that so. What the reduction changes is the orthogonality defect — the product of the basis vectors' lengths over the determinant — from 40.012 to 1. One is the floor, and it is attained only by an orthogonal basis.the same lattice, twicewhat the reduction may not changedet, before1det, after1defect, before40defect, after1LLL steps1the determinant is the invariantand the defect is what is being reduced

The dots are the lattice generated by (1, 0) and (40, 1) — every one of them, out to ±4 in each coefficient. The long pair of arrows is that basis; the short pair is what LLL returns after 1 steps, in exact rational arithmetic with δ = 3/4. The two bases generate the same set of points, which is checked rather than drawn: the lattice determinant is 1 before and 1 after, and every step of the reduction is a unimodular operation, which is what makes that so. What the reduction changes is the orthogonality defect — the product of the basis vectors' lengths over the determinant — from 40.012 to 1. One is the floor, and it is attained only by an orthogonal basis.

skew: 2

The arguments are the ones A basis that describes its lattice badly passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

One lattice, two bases: an orthogonality defect of 2.236 reduced to 1The dots are the lattice generated by (1, 0) and (2, 1) — every one of them, out to ±4 in each coefficient. The long pair of arrows is that basis; the short pair is what LLL returns after 1 steps, in exact rational arithmetic with δ = 3/4. The two bases generate the same set of points, which is checked rather than drawn: the lattice determinant is 1 before and 1 after, and every step of the reduction is a unimodular operation, which is what makes that so. What the reduction changes is the orthogonality defect — the product of the basis vectors' lengths over the determinant — from 2.2361 to 1. One is the floor, and it is attained only by an orthogonal basis.the same lattice, twicewhat the reduction may not changedet, before1det, after1defect, before2.2defect, after1LLL steps1the determinant is the invariantand the defect is what is being reduced

The dots are the lattice generated by (1, 0) and (2, 1) — every one of them, out to ±4 in each coefficient. The long pair of arrows is that basis; the short pair is what LLL returns after 1 steps, in exact rational arithmetic with δ = 3/4. The two bases generate the same set of points, which is checked rather than drawn: the lattice determinant is 1 before and 1 after, and every step of the reduction is a unimodular operation, which is what makes that so. What the reduction changes is the orthogonality defect — the product of the basis vectors' lengths over the determinant — from 2.2361 to 1. One is the floor, and it is attained only by an orthogonal basis.

skew: 5

The arguments are the ones A basis that describes its lattice badly passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

One lattice, two bases: an orthogonality defect of 5.099 reduced to 1The dots are the lattice generated by (1, 0) and (5, 1) — every one of them, out to ±4 in each coefficient. The long pair of arrows is that basis; the short pair is what LLL returns after 1 steps, in exact rational arithmetic with δ = 3/4. The two bases generate the same set of points, which is checked rather than drawn: the lattice determinant is 1 before and 1 after, and every step of the reduction is a unimodular operation, which is what makes that so. What the reduction changes is the orthogonality defect — the product of the basis vectors' lengths over the determinant — from 5.099 to 1. One is the floor, and it is attained only by an orthogonal basis.the same lattice, twicewhat the reduction may not changedet, before1det, after1defect, before5.1defect, after1LLL steps1the determinant is the invariantand the defect is what is being reduced

The dots are the lattice generated by (1, 0) and (5, 1) — every one of them, out to ±4 in each coefficient. The long pair of arrows is that basis; the short pair is what LLL returns after 1 steps, in exact rational arithmetic with δ = 3/4. The two bases generate the same set of points, which is checked rather than drawn: the lattice determinant is 1 before and 1 after, and every step of the reduction is a unimodular operation, which is what makes that so. What the reduction changes is the orthogonality defect — the product of the basis vectors' lengths over the determinant — from 5.099 to 1. One is the floor, and it is attained only by an orthogonal basis.

skew: 12

The arguments are the ones A basis that describes its lattice badly passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

One lattice, two bases: an orthogonality defect of 12.04 reduced to 1The dots are the lattice generated by (1, 0) and (12, 1) — every one of them, out to ±4 in each coefficient. The long pair of arrows is that basis; the short pair is what LLL returns after 1 steps, in exact rational arithmetic with δ = 3/4. The two bases generate the same set of points, which is checked rather than drawn: the lattice determinant is 1 before and 1 after, and every step of the reduction is a unimodular operation, which is what makes that so. What the reduction changes is the orthogonality defect — the product of the basis vectors' lengths over the determinant — from 12.042 to 1. One is the floor, and it is attained only by an orthogonal basis.the same lattice, twicewhat the reduction may not changedet, before1det, after1defect, before12defect, after1LLL steps1the determinant is the invariantand the defect is what is being reduced

The dots are the lattice generated by (1, 0) and (12, 1) — every one of them, out to ±4 in each coefficient. The long pair of arrows is that basis; the short pair is what LLL returns after 1 steps, in exact rational arithmetic with δ = 3/4. The two bases generate the same set of points, which is checked rather than drawn: the lattice determinant is 1 before and 1 after, and every step of the reduction is a unimodular operation, which is what makes that so. What the reduction changes is the orthogonality defect — the product of the basis vectors' lengths over the determinant — from 12.042 to 1. One is the floor, and it is attained only by an orthogonal basis.

What it checked while drawing

Every figure above asserted its own claims on the way to being drawn, and a claim that failed would have failed the build rather than drawn a wrong picture. Those assertions used to leave no trace at all: a passing one returned true and the only evidence the figure had checked anything was that nothing crashed. The list below is what they actually said, collected by running this generator with an observer installed — not a description of what it is believed to check.

7 distinct claims across 6 sets of arguments, grouped below by shape — because most of them are one sentence with a different number in it, and how many separate times that sentence was put to the test is the informative part.

an LLL-reduced basis is integral

and does not make the basis worse

every Bareiss division is exact

how badly skewed the starting basis is

LLL does not change the lattice determinant

LLL terminates on this basis

the assertion refuses a counterexample

Against the rule

The rule does not apply to it. It factorises nothing, so there is no residual it could be withholding. That is worth stating rather than leaving blank: a site that reported the rule as satisfied by every generator would be counting mostly generators the rule never reached.

Across the library: the rule bites on 214 of 397 generators — 194 print a residual and 20 are exempt with a published reason; 183 factorise nothing. Read from lib/residual-rule.js, which is the same body the gate enforces from, and the gate's last check fails the build if this page and it disagree about any generator.

Where it is called

Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.

Exact arithmetic, and what it costs instead

A basis that describes its lattice badly

The same set of points has infinitely many bases, they are all correct, and they are not equally useful. One measurement separates them — the product of the vectors' lengths over the lattice determinant — and the determinant is the invariant the reduction may not change, which is what makes the reduction checkable.

Exact arithmetic, and what it costs instead

A fraction recovered from one remainder

A solution over the rationals can be computed modulo a prime power and then recovered — the residue determines the fraction uniquely, but only once the modulus is twice the square of the fraction's longer part. Below that there is no partial credit: the algorithm returns a different fraction with the same residue, and it is a perfectly good one.

Exact arithmetic, and what it costs instead

Every intermediate is a minor

Fraction-free elimination divides by the previous pivot at every step and the division is always exact. Not usually, not for these entries — always, because the number being divided is a determinant with that pivot as a factor, which is a theorem and is checked here against the minors themselves.

Exact arithmetic, and what it costs instead

How many primes the answer needs

Work modulo a word-sized prime and no intermediate can exceed twenty-six bits, whatever the matrix does. The catch is that the answer must be reassembled from several such computations, and the number of them has to be fixed before the first one runs — by a theorem about how large a determinant can be, not by trying more until it settles.

Exact arithmetic, and what it costs instead

The answer is longer than the question

An exact solution of an integer system is a vector of fractions, each of them a ratio of two determinants. So the output carries 2n long integers where the input carried n² short ones, and no algorithm can write it down more cheaply — the length of the answer is a floor under every exact solver rather than a property of one.

Exact arithmetic, and what it costs instead

The rank depends on the ring

A floating-point rank is a decision about a threshold. Remove the arithmetic error entirely and the threshold goes away — and the answer still is not a property of the array of numbers, because one integer matrix has rank six over the rationals, five modulo three and four modulo two, with nothing rounded and nothing decided.

Exact arithmetic, and what it costs instead

What a determinant does not determine

Two integer matrices can have the same determinant, the same rank and the same size, and define genuinely different maps. What separates them is a list of integers each dividing the next — computed here twice, once by unimodular elimination and once from the gcds of every minor, which share no algorithm at all.

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