Generator

The error of a reduction is a walk, and the number of pieces changes which walk

One function in the repro library, called 7 times across 2 essays. Below: what it draws at its defaults, what it draws at every value an essay asks for, the 5 claims it put to the test while drawing them, and where it stands against the rule this site is named for.

At its defaults it draws the error of a reduction is a walk, and the number of pieces changes which walk. Running error of two reductions of the same 2048 numbers, against how many terms have been consumed: one accumulator, and 8 pieces combined at the end. Each is the distance between what the arithmetic has accumulated so far and the exact sum of the same terms, carried in a compensated pair so the instrument does not round. The two separate within the first few terms and never meet again, ending at 7.56·10⁻¹⁴ and 2.41·10⁻¹⁴. The mechanism is in the horizontal axis: a rounding is committed at every partial sum and its size is that partial sum's spacing, and this vector's running total reaches 32.1 on the way to an answer of 1.63·10⁻⁵. Dividing the work shortens each walk, so the mean error over eight vectors falls from 4.78·10⁻¹⁴ at one piece to 8.14·10⁻¹⁵ at sixty-four: more workers is more accurate, which is the opposite of what the word *parallel* suggests here.

partial-walk is one function in lib/figures/repro.js — one sum, several answers — what a reduction's division costs, and the two policies that remove it. Everything below came out of it during this build, at arguments taken from the essays rather than invented for this page. A figure here is the figure a reader meets in an essay, and if the generator changes, this page changes with it.

At its defaults

Drawn even though every essay passes arguments — which on this site is every essay, at 100% of placements since the standard pass. A default nothing exercises is a trap for the next essay to call this with none, and this is the page where a default that has drifted from the figures around it becomes visible.

The error of a reduction is a walk, and the number of pieces changes which walkRunning error of two reductions of the same 2048 numbers, against how many terms have been consumed: one accumulator, and 8 pieces combined at the end. Each is the distance between what the arithmetic has accumulated so far and the exact sum of the same terms, carried in a compensated pair so the instrument does not round. The two separate within the first few terms and never meet again, ending at 7.56·10⁻¹⁴ and 2.41·10⁻¹⁴. The mechanism is in the horizontal axis: a rounding is committed at every partial sum and its size is that partial sum's spacing, and this vector's running total reaches 32.1 on the way to an answer of 1.63·10⁻⁵. Dividing the work shortens each walk, so the mean error over eight vectors falls from 4.78·10⁻¹⁴ at one piece to 8.14·10⁻¹⁵ at sixty-four: more workers is more accurate, which is the opposite of what the word *parallel* suggests here.051210241536204810⁻¹⁷10⁻¹⁴terms consumederror accumulated so farone accumulator8 piecesthe steps are the partial sumspeak partial sum32the answer1.6·10⁻⁵error, one piece7.6·10⁻¹⁴error, 8 pieces2.4·10⁻¹⁴mean at p = 648.1·10⁻¹⁵the walk sets the sizeand nothing sets the value

Running error of two reductions of the same 2048 numbers, against how many terms have been consumed: one accumulator, and 8 pieces combined at the end. Each is the distance between what the arithmetic has accumulated so far and the exact sum of the same terms, carried in a compensated pair so the instrument does not round. The two separate within the first few terms and never meet again, ending at 7.56·10⁻¹⁴ and 2.41·10⁻¹⁴. The mechanism is in the horizontal axis: a rounding is committed at every partial sum and its size is that partial sum's spacing, and this vector's running total reaches 32.1 on the way to an answer of 1.63·10⁻⁵. Dividing the work shortens each walk, so the mean error over eight vectors falls from 4.78·10⁻¹⁴ at one piece to 8.14·10⁻¹⁵ at sixty-four: more workers is more accurate, which is the opposite of what the word *parallel* suggests here.

p: 8

The arguments are the ones The same program, twice passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

The error of a reduction is a walk, and the number of pieces changes which walkRunning error of two reductions of the same 2048 numbers, against how many terms have been consumed: one accumulator, and 8 pieces combined at the end. Each is the distance between what the arithmetic has accumulated so far and the exact sum of the same terms, carried in a compensated pair so the instrument does not round. The two separate within the first few terms and never meet again, ending at 7.56·10⁻¹⁴ and 2.41·10⁻¹⁴. The mechanism is in the horizontal axis: a rounding is committed at every partial sum and its size is that partial sum's spacing, and this vector's running total reaches 32.1 on the way to an answer of 1.63·10⁻⁵. Dividing the work shortens each walk, so the mean error over eight vectors falls from 4.78·10⁻¹⁴ at one piece to 8.14·10⁻¹⁵ at sixty-four: more workers is more accurate, which is the opposite of what the word *parallel* suggests here.051210241536204810⁻¹⁷10⁻¹⁴terms consumederror accumulated so farone accumulator8 piecesthe steps are the partial sumspeak partial sum32the answer1.6·10⁻⁵error, one piece7.6·10⁻¹⁴error, 8 pieces2.4·10⁻¹⁴mean at p = 648.1·10⁻¹⁵the walk sets the sizeand nothing sets the value

Running error of two reductions of the same 2048 numbers, against how many terms have been consumed: one accumulator, and 8 pieces combined at the end. Each is the distance between what the arithmetic has accumulated so far and the exact sum of the same terms, carried in a compensated pair so the instrument does not round. The two separate within the first few terms and never meet again, ending at 7.56·10⁻¹⁴ and 2.41·10⁻¹⁴. The mechanism is in the horizontal axis: a rounding is committed at every partial sum and its size is that partial sum's spacing, and this vector's running total reaches 32.1 on the way to an answer of 1.63·10⁻⁵. Dividing the work shortens each walk, so the mean error over eight vectors falls from 4.78·10⁻¹⁴ at one piece to 8.14·10⁻¹⁵ at sixty-four: more workers is more accurate, which is the opposite of what the word *parallel* suggests here.

p: 2

The arguments are the ones Where the disagreement comes from passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

The error of a reduction is a walk, and the number of pieces changes which walkRunning error of two reductions of the same 2048 numbers, against how many terms have been consumed: one accumulator, and 2 pieces combined at the end. Each is the distance between what the arithmetic has accumulated so far and the exact sum of the same terms, carried in a compensated pair so the instrument does not round. The two separate within the first few terms and never meet again, ending at 7.56·10⁻¹⁴ and 1.13·10⁻¹³. The mechanism is in the horizontal axis: a rounding is committed at every partial sum and its size is that partial sum's spacing, and this vector's running total reaches 32.1 on the way to an answer of 1.63·10⁻⁵. Dividing the work shortens each walk, so the mean error over eight vectors falls from 4.78·10⁻¹⁴ at one piece to 8.14·10⁻¹⁵ at sixty-four: more workers is more accurate, which is the opposite of what the word *parallel* suggests here.051210241536204810⁻¹⁷10⁻¹⁴terms consumederror accumulated so farone accumulator2 piecesthe steps are the partial sumspeak partial sum32the answer1.6·10⁻⁵error, one piece7.6·10⁻¹⁴error, 2 pieces1.1·10⁻¹³mean at p = 648.1·10⁻¹⁵the walk sets the sizeand nothing sets the value

Running error of two reductions of the same 2048 numbers, against how many terms have been consumed: one accumulator, and 2 pieces combined at the end. Each is the distance between what the arithmetic has accumulated so far and the exact sum of the same terms, carried in a compensated pair so the instrument does not round. The two separate within the first few terms and never meet again, ending at 7.56·10⁻¹⁴ and 1.13·10⁻¹³. The mechanism is in the horizontal axis: a rounding is committed at every partial sum and its size is that partial sum's spacing, and this vector's running total reaches 32.1 on the way to an answer of 1.63·10⁻⁵. Dividing the work shortens each walk, so the mean error over eight vectors falls from 4.78·10⁻¹⁴ at one piece to 8.14·10⁻¹⁵ at sixty-four: more workers is more accurate, which is the opposite of what the word *parallel* suggests here.

p: 4

The arguments are the ones Where the disagreement comes from passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

The error of a reduction is a walk, and the number of pieces changes which walkRunning error of two reductions of the same 2048 numbers, against how many terms have been consumed: one accumulator, and 4 pieces combined at the end. Each is the distance between what the arithmetic has accumulated so far and the exact sum of the same terms, carried in a compensated pair so the instrument does not round. The two separate within the first few terms and never meet again, ending at 7.56·10⁻¹⁴ and 4.71·10⁻¹⁴. The mechanism is in the horizontal axis: a rounding is committed at every partial sum and its size is that partial sum's spacing, and this vector's running total reaches 32.1 on the way to an answer of 1.63·10⁻⁵. Dividing the work shortens each walk, so the mean error over eight vectors falls from 4.78·10⁻¹⁴ at one piece to 8.14·10⁻¹⁵ at sixty-four: more workers is more accurate, which is the opposite of what the word *parallel* suggests here.051210241536204810⁻¹⁷10⁻¹⁴terms consumederror accumulated so farone accumulator4 piecesthe steps are the partial sumspeak partial sum32the answer1.6·10⁻⁵error, one piece7.6·10⁻¹⁴error, 4 pieces4.7·10⁻¹⁴mean at p = 648.1·10⁻¹⁵the walk sets the sizeand nothing sets the value

Running error of two reductions of the same 2048 numbers, against how many terms have been consumed: one accumulator, and 4 pieces combined at the end. Each is the distance between what the arithmetic has accumulated so far and the exact sum of the same terms, carried in a compensated pair so the instrument does not round. The two separate within the first few terms and never meet again, ending at 7.56·10⁻¹⁴ and 4.71·10⁻¹⁴. The mechanism is in the horizontal axis: a rounding is committed at every partial sum and its size is that partial sum's spacing, and this vector's running total reaches 32.1 on the way to an answer of 1.63·10⁻⁵. Dividing the work shortens each walk, so the mean error over eight vectors falls from 4.78·10⁻¹⁴ at one piece to 8.14·10⁻¹⁵ at sixty-four: more workers is more accurate, which is the opposite of what the word *parallel* suggests here.

p: 16

The arguments are the ones Where the disagreement comes from passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

The error of a reduction is a walk, and the number of pieces changes which walkRunning error of two reductions of the same 2048 numbers, against how many terms have been consumed: one accumulator, and 16 pieces combined at the end. Each is the distance between what the arithmetic has accumulated so far and the exact sum of the same terms, carried in a compensated pair so the instrument does not round. The two separate within the first few terms and never meet again, ending at 7.56·10⁻¹⁴ and 2.76·10⁻¹⁴. The mechanism is in the horizontal axis: a rounding is committed at every partial sum and its size is that partial sum's spacing, and this vector's running total reaches 32.1 on the way to an answer of 1.63·10⁻⁵. Dividing the work shortens each walk, so the mean error over eight vectors falls from 4.78·10⁻¹⁴ at one piece to 8.14·10⁻¹⁵ at sixty-four: more workers is more accurate, which is the opposite of what the word *parallel* suggests here.051210241536204810⁻¹⁷10⁻¹⁴terms consumederror accumulated so farone accumulator16 piecesthe steps are the partial sumspeak partial sum32the answer1.6·10⁻⁵error, one piece7.6·10⁻¹⁴error, 16 pieces2.8·10⁻¹⁴mean at p = 648.1·10⁻¹⁵the walk sets the sizeand nothing sets the value

Running error of two reductions of the same 2048 numbers, against how many terms have been consumed: one accumulator, and 16 pieces combined at the end. Each is the distance between what the arithmetic has accumulated so far and the exact sum of the same terms, carried in a compensated pair so the instrument does not round. The two separate within the first few terms and never meet again, ending at 7.56·10⁻¹⁴ and 2.76·10⁻¹⁴. The mechanism is in the horizontal axis: a rounding is committed at every partial sum and its size is that partial sum's spacing, and this vector's running total reaches 32.1 on the way to an answer of 1.63·10⁻⁵. Dividing the work shortens each walk, so the mean error over eight vectors falls from 4.78·10⁻¹⁴ at one piece to 8.14·10⁻¹⁵ at sixty-four: more workers is more accurate, which is the opposite of what the word *parallel* suggests here.

p: 64

The arguments are the ones Where the disagreement comes from passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

The error of a reduction is a walk, and the number of pieces changes which walkRunning error of two reductions of the same 2048 numbers, against how many terms have been consumed: one accumulator, and 64 pieces combined at the end. Each is the distance between what the arithmetic has accumulated so far and the exact sum of the same terms, carried in a compensated pair so the instrument does not round. The two separate within the first few terms and never meet again, ending at 7.56·10⁻¹⁴ and 2.74·10⁻¹⁵. The mechanism is in the horizontal axis: a rounding is committed at every partial sum and its size is that partial sum's spacing, and this vector's running total reaches 32.1 on the way to an answer of 1.63·10⁻⁵. Dividing the work shortens each walk, so the mean error over eight vectors falls from 4.78·10⁻¹⁴ at one piece to 8.14·10⁻¹⁵ at sixty-four: more workers is more accurate, which is the opposite of what the word *parallel* suggests here.051210241536204810⁻¹⁹10⁻¹⁶10⁻¹³terms consumederror accumulated so farone accumulator64 piecesthe steps are the partial sumspeak partial sum32the answer1.6·10⁻⁵error, one piece7.6·10⁻¹⁴error, 64 pieces2.7·10⁻¹⁵mean at p = 648.1·10⁻¹⁵the walk sets the sizeand nothing sets the value

Running error of two reductions of the same 2048 numbers, against how many terms have been consumed: one accumulator, and 64 pieces combined at the end. Each is the distance between what the arithmetic has accumulated so far and the exact sum of the same terms, carried in a compensated pair so the instrument does not round. The two separate within the first few terms and never meet again, ending at 7.56·10⁻¹⁴ and 2.74·10⁻¹⁵. The mechanism is in the horizontal axis: a rounding is committed at every partial sum and its size is that partial sum's spacing, and this vector's running total reaches 32.1 on the way to an answer of 1.63·10⁻⁵. Dividing the work shortens each walk, so the mean error over eight vectors falls from 4.78·10⁻¹⁴ at one piece to 8.14·10⁻¹⁵ at sixty-four: more workers is more accurate, which is the opposite of what the word *parallel* suggests here.

What it checked while drawing

Every figure above checked its own claims on the way to being drawn, and a claim that failed would have stopped the picture rather than shipped a wrong one. Those checks used to leave no trace at all: a passing one returned true and the only evidence the figure had checked anything was that nothing crashed. The list below is what they actually said, collected by running this generator with an observer installed — not a description of what it is believed to check.

5 distinct claims across 6 sets of arguments, grouped below by shape — because most of them are one sentence with a different number in it, and how many separate times that sentence was put to the test is the informative part.

a partition count a machine might have

a vector the walk can be drawn over

and dividing the reduction further makes it more accurate, not less

the running total dwarfs the answer, which is what cancellation is

two partitionings end at two different errors

Against the rule

The rule does not apply to it. It factorises nothing, so there is no residual it could be withholding. That is worth stating rather than leaving blank: a site that reported the rule as satisfied by every generator would be counting mostly generators the rule never reached.

Across the library: the rule bites on 217 of 397 generators — 199 print a residual and 18 are exempt with a published reason; 180 factorise nothing. Read from lib/residual-rule.js, which is the same body the gate enforces from, and the gate's last check fails the build if this page and it disagree about any generator.

Where it is called

Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.

The whole library · All essays · What must fail