Generator

Elimination with and without pivoting, ε = 10⁻¹⁷

One function in the elim library, called 8 times across 1 essay. Below: what it draws at its defaults, what it draws at every value an essay asks for, the 5 claims it put to the test while drawing them, and where it stands against the rule this site is named for.

At its defaults it draws elimination with and without pivoting, ε = 10⁻¹⁷. The same two-by-two system solved twice. With a row swap the answer is exact; without one the upper triangular factor contains an entry of order one over epsilon and the second component of the answer is wrong.

pivot-failure is one function in lib/figures/elim.js — elimination — the swap, the growth factor, and the matrix with a known answer. Everything below came out of it during this build, at arguments taken from the essays rather than invented for this page. A figure here is the figure a reader meets in an essay, and if the generator changes, this page changes with it.

At its defaults

Drawn even though every essay passes arguments — which on this site is every essay, at 100% of placements since the standard pass. A default nothing exercises is a trap for the next essay to call this with none, and this is the page where a default that has drifted from the figures around it becomes visible.

Elimination with and without pivoting, ε = 10⁻¹⁷The same two-by-two system solved twice. With a row swap the answer is exact; without one the upper triangular factor contains an entry of order one over epsilon and the second component of the answer is wrong.[ ε 1 ; 1 1 ] x = [ 1 ; 2 ], exact answer (1.000000, 1.000000)with partial pivoting1101U after elimination1.0000001.000000computed xbackward error 0forward error 0without10⁻¹⁷10-1·10¹⁷U after elimination0.0000001.000000computed xbackward error 0.25forward error 0.71no error is raisedgrowth 10¹⁷

The same two-by-two system solved twice. With a row swap the answer is exact; without one the upper triangular factor contains an entry of order one over epsilon and the second component of the answer is wrong.

logEps: -17

The arguments are the ones The swap that is not optional passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

Elimination with and without pivoting, ε = 10⁻¹⁷The same two-by-two system solved twice. With a row swap the answer is exact; without one the upper triangular factor contains an entry of order one over epsilon and the second component of the answer is wrong.[ ε 1 ; 1 1 ] x = [ 1 ; 2 ], exact answer (1.000000, 1.000000)with partial pivoting1101U after elimination1.0000001.000000computed xbackward error 0forward error 0without10⁻¹⁷10-1·10¹⁷U after elimination0.0000001.000000computed xbackward error 0.25forward error 0.71no error is raisedgrowth 10¹⁷

The same two-by-two system solved twice. With a row swap the answer is exact; without one the upper triangular factor contains an entry of order one over epsilon and the second component of the answer is wrong.

logEps: -3

The arguments are the ones The swap that is not optional passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

Elimination with and without pivoting, ε = 0.001The same two-by-two system solved twice. With a row swap the answer is exact; without one the upper triangular factor contains an entry of order one over epsilon and the second component of the answer is wrong.[ ε 1 ; 1 1 ] x = [ 1 ; 2 ], exact answer (1.001001, 0.998999)with partial pivoting1100.999U after elimination1.0010010.998999computed xbackward error 0forward error 0without0.00110-999U after elimination1.0010010.998999computed xbackward error 5.7·10⁻¹⁵forward error 1.6·10⁻¹⁴no error is raisedgrowth 999

The same two-by-two system solved twice. With a row swap the answer is exact; without one the upper triangular factor contains an entry of order one over epsilon and the second component of the answer is wrong.

logEps: -5

The arguments are the ones The swap that is not optional passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

Elimination with and without pivoting, ε = 10⁻⁵The same two-by-two system solved twice. With a row swap the answer is exact; without one the upper triangular factor contains an entry of order one over epsilon and the second component of the answer is wrong.[ ε 1 ; 1 1 ] x = [ 1 ; 2 ], exact answer (1.000010, 0.999990)with partial pivoting1101U after elimination1.0000100.999990computed xbackward error 2.8·10⁻¹⁷forward error 0without10⁻⁵10-100000U after elimination1.0000100.999990computed xbackward error 9.5·10⁻¹³forward error 2.7·10⁻¹²no error is raisedgrowth 10·10⁴

The same two-by-two system solved twice. With a row swap the answer is exact; without one the upper triangular factor contains an entry of order one over epsilon and the second component of the answer is wrong.

logEps: -8

The arguments are the ones The swap that is not optional passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

Elimination with and without pivoting, ε = 10⁻⁸The same two-by-two system solved twice. With a row swap the answer is exact; without one the upper triangular factor contains an entry of order one over epsilon and the second component of the answer is wrong.[ ε 1 ; 1 1 ] x = [ 1 ; 2 ], exact answer (1.000000, 1.000000)with partial pivoting1101U after elimination1.0000001.000000computed xbackward error 0forward error 1.6·10⁻¹⁶without10⁻⁸10-10·10⁷U after elimination1.0000001.000000computed xbackward error 1.2·10⁻⁹forward error 3.5·10⁻⁹no error is raisedgrowth 10·10⁷

The same two-by-two system solved twice. With a row swap the answer is exact; without one the upper triangular factor contains an entry of order one over epsilon and the second component of the answer is wrong.

logEps: -11

The arguments are the ones The swap that is not optional passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

Elimination with and without pivoting, ε = 10⁻¹¹The same two-by-two system solved twice. With a row swap the answer is exact; without one the upper triangular factor contains an entry of order one over epsilon and the second component of the answer is wrong.[ ε 1 ; 1 1 ] x = [ 1 ; 2 ], exact answer (1.000000, 1.000000)with partial pivoting1101U after elimination1.0000001.000000computed xbackward error 0forward error 0without10⁻¹¹10-10·10¹⁰U after elimination1.0000001.000000computed xbackward error 2.1·10⁻⁸forward error 5.8·10⁻⁸no error is raisedgrowth 10·10¹⁰

The same two-by-two system solved twice. With a row swap the answer is exact; without one the upper triangular factor contains an entry of order one over epsilon and the second component of the answer is wrong.

What it checked while drawing

Every figure above checked its own claims on the way to being drawn, and a claim that failed would have stopped the picture rather than shipped a wrong one. Those checks used to leave no trace at all: a passing one returned true and the only evidence the figure had checked anything was that nothing crashed. The list below is what they actually said, collected by running this generator with an observer installed — not a description of what it is believed to check.

5 distinct claims across 6 sets of arguments, grouped below by shape — because most of them are one sentence with a different number in it, and how many separate times that sentence was put to the test is the informative part.

and the unpivoted one is worse

elimination without the swap multiplies the entries by 1/ε agree

LU is for square matrices

the closed-form solution, written two ways agree

the pivoted solve is backward stable

Against the rule

It calls a factoriser without drawing a factorisation (luFactor, solve), so the rule is written down as not applying, with the reason: prints backward and forward error for both runs, which is the stronger statement here

The exemption list is the interesting half of the rule rather than an escape hatch — it is where a decision about a figure had to be argued in one line. residualcheck refuses an exemption that is not doing work, and rejected ten of the fifteen written for the expansion's figures on exactly that ground: a figure whose vertical axis is a residual satisfies the rule by construction, and touching a factoriser does not by itself require an entry.

Across the library: the rule bites on 217 of 397 generators — 199 print a residual and 18 are exempt with a published reason; 180 factorise nothing. Read from lib/residual-rule.js, which is the same body the gate enforces from, and the gate's last check fails the build if this page and it disagree about any generator.

Where it is called

Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.

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