Generator

rank-floor

One function in the ttrain library, called 3 times across 3 essays. Below: what it draws at its defaults, what it draws at every value an essay asks for, the 4 claims it put to the test while drawing them, and where it stands against the rule this site is named for.

At its defaults it draws the residual a rank budget leaves, against the budget, on two right-hand sides of the same operator. Both runs use the same method on the same matrix for 70 steps and differ only in b. With a constant right-hand side the floor falls 0.118, 0.0107, 3.61·10⁻⁴, 5.4·10⁻⁶, 1.07·10⁻¹³, 1.07·10⁻¹³, 1.07·10⁻¹³ — about two decades per column — and disappears at rank 5, because the solution *is* a train of that rank and the truncation has stopped removing anything. With independent normal entries the same ladder gives 0.969, 0.925, 0.874, 0.801, 0.735, 0.656, 0.47: 8 columns of a 10-column answer buy a factor of 2.06. So a floor is not a property of the truncation. It is the distance from the answer to the set the truncation projects onto, and the same budget is free on one problem and useless on the next.

rank-floor is one function in lib/figures/ttrain.js — the train — one rank per cut of the index list, and the iterate that must be cut back. Everything below came out of it during this build, at arguments taken from the essays rather than invented for this page. A figure here is the figure a reader meets in an essay, and if the generator changes, this page changes with it.

At its defaults

Drawn even though every essay passes arguments — which on this site is every essay, at 100% of placements since the standard pass. A default nothing exercises is a trap for the next essay to call this with none, and this is the page where a default that has drifted from the figures around it becomes visible.

The residual a rank budget leaves, against the budget, on two right-hand sides of the same operatorBoth runs use the same method on the same matrix for 70 steps and differ only in b. With a constant right-hand side the floor falls 0.118, 0.0107, 3.61·10⁻⁴, 5.4·10⁻⁶, 1.07·10⁻¹³, 1.07·10⁻¹³, 1.07·10⁻¹³ — about two decades per column — and disappears at rank 5, because the solution *is* a train of that rank and the truncation has stopped removing anything. With independent normal entries the same ladder gives 0.969, 0.925, 0.874, 0.801, 0.735, 0.656, 0.47: 8 columns of a 10-column answer buy a factor of 2.06. So a floor is not a property of the truncation. It is the distance from the answer to the set the truncation projects onto, and the same budget is free on one problem and useless on the next.012345678910⁻¹³10⁻¹⁰10⁻⁷10⁻⁴10⁻¹rank budgetresidual the run stalls atb with no structure at allb constant: the answer is a traintwo ladders, one truncationstructured, rank 10.12structured, rank 45.4·10⁻⁶structured, rank 81.1·10⁻¹³unstructured, rank 10.97unstructured, rank 80.47the floor is not the truncation'sit is the answer's

Both runs use the same method on the same matrix for 70 steps and differ only in b. With a constant right-hand side the floor falls 0.118, 0.0107, 3.61·10⁻⁴, 5.4·10⁻⁶, 1.07·10⁻¹³, 1.07·10⁻¹³, 1.07·10⁻¹³ — about two decades per column — and disappears at rank 5, because the solution *is* a train of that rank and the truncation has stopped removing anything. With independent normal entries the same ladder gives 0.969, 0.925, 0.874, 0.801, 0.735, 0.656, 0.47: 8 columns of a 10-column answer buy a factor of 2.06. So a floor is not a property of the truncation. It is the distance from the answer to the set the truncation projects onto, and the same budget is free on one problem and useless on the next.

steps: 70

The arguments are the ones An iterate that must be made smaller passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

The residual a rank budget leaves, against the budget, on two right-hand sides of the same operatorBoth runs use the same method on the same matrix for 70 steps and differ only in b. With a constant right-hand side the floor falls 0.118, 0.0107, 3.61·10⁻⁴, 5.4·10⁻⁶, 1.07·10⁻¹³, 1.07·10⁻¹³, 1.07·10⁻¹³ — about two decades per column — and disappears at rank 5, because the solution *is* a train of that rank and the truncation has stopped removing anything. With independent normal entries the same ladder gives 0.969, 0.925, 0.874, 0.801, 0.735, 0.656, 0.47: 8 columns of a 10-column answer buy a factor of 2.06. So a floor is not a property of the truncation. It is the distance from the answer to the set the truncation projects onto, and the same budget is free on one problem and useless on the next.012345678910⁻¹³10⁻¹⁰10⁻⁷10⁻⁴10⁻¹rank budgetresidual the run stalls atb with no structure at allb constant: the answer is a traintwo ladders, one truncationstructured, rank 10.12structured, rank 45.4·10⁻⁶structured, rank 81.1·10⁻¹³unstructured, rank 10.97unstructured, rank 80.47the floor is not the truncation'sit is the answer's

Both runs use the same method on the same matrix for 70 steps and differ only in b. With a constant right-hand side the floor falls 0.118, 0.0107, 3.61·10⁻⁴, 5.4·10⁻⁶, 1.07·10⁻¹³, 1.07·10⁻¹³, 1.07·10⁻¹³ — about two decades per column — and disappears at rank 5, because the solution *is* a train of that rank and the truncation has stopped removing anything. With independent normal entries the same ladder gives 0.969, 0.925, 0.874, 0.801, 0.735, 0.656, 0.47: 8 columns of a 10-column answer buy a factor of 2.06. So a floor is not a property of the truncation. It is the distance from the answer to the set the truncation projects onto, and the same budget is free on one problem and useless on the next.

What it checked while drawing

Every figure above asserted its own claims on the way to being drawn, and a claim that failed would have failed the build rather than drawn a wrong picture. Those assertions used to leave no trace at all: a passing one returned true and the only evidence the figure had checked anything was that nothing crashed. The list below is what they actually said, collected by running this generator with an observer installed — not a description of what it is believed to check.

4 distinct claims across 2 sets of arguments, grouped below by shape — because most of them are one sentence with a different number in it, and how many separate times that sentence was put to the test is the informative part.

a run long enough to have reached its floor

and the unstructured answer is nowhere near reached

matmul shapes agree

one more column never raises the floor

Against the rule

The rule does not apply to it. It factorises nothing, so there is no residual it could be withholding. That is worth stating rather than leaving blank: a site that reported the rule as satisfied by every generator would be counting mostly generators the rule never reached.

Across the library: the rule bites on 146 of 287 generators — 131 print a residual and 15 are exempt with a published reason; 141 factorise nothing. Read from lib/residual-rule.js, which is the same body the gate enforces from, and the gate's last check fails the build if this page and it disagree about any generator.

Where it is called

Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.

The whole library · All essays · What must fail