Generator

reciprocal-pairs

One function in the palindromic library, called 16 times across 5 essays. Below: what it draws at its defaults, what it draws at every value an essay asks for, the 15 claims it put to the test while drawing them, and where it stands against the rule this site is named for.

At its defaults it draws the 12 eigenvalues of a palindromic quadratic, in 6 pairs whose products are one. λ²A + λB + Aᵀ with A and B symmetric reads the same backwards, so λ is an eigenvalue exactly when 1/λ is. The axis is log₁₀|λ|, the marks are the computed eigenvalues and each arc joins a pair; the vertical line is |λ| = 1, about which the whole picture is symmetric. The spectrum spans 9.56 decades at b = 10⁴. Measured, the general solver's spectrum departs from being closed under λ ↦ 1/λ by 3.27·10⁻⁹, and the structured route's — one symmetric generalised eigenvalue problem of size 6 rather than an unsymmetric one of size 12 — by 2.21·10⁻¹⁶, which is the rounding level and is by construction.

reciprocal-pairs is one function in lib/figures/palindromic.js — reciprocal pairs — a symmetry the solver discards, and the division that is worth seven orders. Everything below came out of it during this build, at arguments taken from the essays rather than invented for this page. A figure here is the figure a reader meets in an essay, and if the generator changes, this page changes with it.

At its defaults

Drawn even though every essay passes arguments — which on this site is every essay, at 100% of placements since the standard pass. A default nothing exercises is a trap for the next essay to call this with none, and this is the page where a default that has drifted from the figures around it becomes visible.

The 12 eigenvalues of a palindromic quadratic, in 6 pairs whose products are oneλ²A + λB + Aᵀ with A and B symmetric reads the same backwards, so λ is an eigenvalue exactly when 1/λ is. The axis is log₁₀|λ|, the marks are the computed eigenvalues and each arc joins a pair; the vertical line is |λ| = 1, about which the whole picture is symmetric. The spectrum spans 9.56 decades at b = 10⁴. Measured, the general solver's spectrum departs from being closed under λ ↦ 1/λ by 3.27·10⁻⁹, and the structured route's — one symmetric generalised eigenvalue problem of size 6 rather than an unsymmetric one of size 12 — by 2.21·10⁻¹⁶, which is the rounding level and is by construction.-5-3.20611-1.412210.3816782.175573.969460log₁₀ |λ||λ| = 1λλ′ = 1, in the algebrapairs6decades of spectrum9.6pairing error, general3.3·10⁻⁹pairing error, structured2.2·10⁻¹⁶a symmetry the solver never knew aboutand the half of the answer it decides

λ²A + λB + Aᵀ with A and B symmetric reads the same backwards, so λ is an eigenvalue exactly when 1/λ is. The axis is log₁₀|λ|, the marks are the computed eigenvalues and each arc joins a pair; the vertical line is |λ| = 1, about which the whole picture is symmetric. The spectrum spans 9.56 decades at b = 10⁴. Measured, the general solver's spectrum departs from being closed under λ ↦ 1/λ by 3.27·10⁻⁹, and the structured route's — one symmetric generalised eigenvalue problem of size 6 rather than an unsymmetric one of size 12 — by 2.21·10⁻¹⁶, which is the rounding level and is by construction.

logB: 4

The arguments are the ones A matrix that depends on its own eigenvalue passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

The 12 eigenvalues of a palindromic quadratic, in 6 pairs whose products are oneλ²A + λB + Aᵀ with A and B symmetric reads the same backwards, so λ is an eigenvalue exactly when 1/λ is. The axis is log₁₀|λ|, the marks are the computed eigenvalues and each arc joins a pair; the vertical line is |λ| = 1, about which the whole picture is symmetric. The spectrum spans 9.56 decades at b = 10⁴. Measured, the general solver's spectrum departs from being closed under λ ↦ 1/λ by 3.27·10⁻⁹, and the structured route's — one symmetric generalised eigenvalue problem of size 6 rather than an unsymmetric one of size 12 — by 2.21·10⁻¹⁶, which is the rounding level and is by construction.-5-3.20611-1.412210.3816782.175573.969460log₁₀ |λ||λ| = 1λλ′ = 1, in the algebrapairs6decades of spectrum9.6pairing error, general3.3·10⁻⁹pairing error, structured2.2·10⁻¹⁶a symmetry the solver never knew aboutand the half of the answer it decides

λ²A + λB + Aᵀ with A and B symmetric reads the same backwards, so λ is an eigenvalue exactly when 1/λ is. The axis is log₁₀|λ|, the marks are the computed eigenvalues and each arc joins a pair; the vertical line is |λ| = 1, about which the whole picture is symmetric. The spectrum spans 9.56 decades at b = 10⁴. Measured, the general solver's spectrum departs from being closed under λ ↦ 1/λ by 3.27·10⁻⁹, and the structured route's — one symmetric generalised eigenvalue problem of size 6 rather than an unsymmetric one of size 12 — by 2.21·10⁻¹⁶, which is the rounding level and is by construction.

logB: 10

The arguments are the ones A perturbation that keeps the symmetry passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

The 12 eigenvalues of a palindromic quadratic, in 6 pairs whose products are oneλ²A + λB + Aᵀ with A and B symmetric reads the same backwards, so λ is an eigenvalue exactly when 1/λ is. The axis is log₁₀|λ|, the marks are the computed eigenvalues and each arc joins a pair; the vertical line is |λ| = 1, about which the whole picture is symmetric. The spectrum spans 21.6 decades at b = 10¹⁰. Measured, the general solver's spectrum departs from being closed under λ ↦ 1/λ by 1.04·10⁻⁷, and the structured route's — one symmetric generalised eigenvalue problem of size 6 rather than an unsymmetric one of size 12 — by 2.32·10⁻¹⁶, which is the rounding level and is by construction.-11-7.20611-3.412210.3816784.175577.969460log₁₀ |λ||λ| = 1λλ′ = 1, in the algebrapairs6decades of spectrum22pairing error, general10⁻⁷pairing error, structured2.3·10⁻¹⁶a symmetry the solver never knew aboutand the half of the answer it decides

λ²A + λB + Aᵀ with A and B symmetric reads the same backwards, so λ is an eigenvalue exactly when 1/λ is. The axis is log₁₀|λ|, the marks are the computed eigenvalues and each arc joins a pair; the vertical line is |λ| = 1, about which the whole picture is symmetric. The spectrum spans 21.6 decades at b = 10¹⁰. Measured, the general solver's spectrum departs from being closed under λ ↦ 1/λ by 1.04·10⁻⁷, and the structured route's — one symmetric generalised eigenvalue problem of size 6 rather than an unsymmetric one of size 12 — by 2.32·10⁻¹⁶, which is the rounding level and is by construction.

logB: 2

The arguments are the ones A perturbation that keeps the symmetry passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

The 12 eigenvalues of a palindromic quadratic, in 6 pairs whose products are oneλ²A + λB + Aᵀ with A and B symmetric reads the same backwards, so λ is an eigenvalue exactly when 1/λ is. The axis is log₁₀|λ|, the marks are the computed eigenvalues and each arc joins a pair; the vertical line is |λ| = 1, about which the whole picture is symmetric. The spectrum spans 5.56 decades at b = 100. Measured, the general solver's spectrum departs from being closed under λ ↦ 1/λ by 5.86·10⁻¹³, and the structured route's — one symmetric generalised eigenvalue problem of size 6 rather than an unsymmetric one of size 12 — by 1.88·10⁻¹⁶, which is the rounding level and is by construction.-3-1.87277-0.7455490.3816761.50892.636130log₁₀ |λ||λ| = 1λλ′ = 1, in the algebrapairs6decades of spectrum5.6pairing error, general5.9·10⁻¹³pairing error, structured1.9·10⁻¹⁶a symmetry the solver never knew aboutand the half of the answer it decides

λ²A + λB + Aᵀ with A and B symmetric reads the same backwards, so λ is an eigenvalue exactly when 1/λ is. The axis is log₁₀|λ|, the marks are the computed eigenvalues and each arc joins a pair; the vertical line is |λ| = 1, about which the whole picture is symmetric. The spectrum spans 5.56 decades at b = 100. Measured, the general solver's spectrum departs from being closed under λ ↦ 1/λ by 5.86·10⁻¹³, and the structured route's — one symmetric generalised eigenvalue problem of size 6 rather than an unsymmetric one of size 12 — by 1.88·10⁻¹⁶, which is the rounding level and is by construction.

logB: 8

The arguments are the ones A perturbation that keeps the symmetry passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

The 12 eigenvalues of a palindromic quadratic, in 6 pairs whose products are oneλ²A + λB + Aᵀ with A and B symmetric reads the same backwards, so λ is an eigenvalue exactly when 1/λ is. The axis is log₁₀|λ|, the marks are the computed eigenvalues and each arc joins a pair; the vertical line is |λ| = 1, about which the whole picture is symmetric. The spectrum spans 17.6 decades at b = 10⁸. Measured, the general solver's spectrum departs from being closed under λ ↦ 1/λ by 9.08·10⁻⁸, and the structured route's — one symmetric generalised eigenvalue problem of size 6 rather than an unsymmetric one of size 12 — by 2.16·10⁻¹⁶, which is the rounding level and is by construction.-9-5.87277-2.745550.3816783.50896.636130log₁₀ |λ||λ| = 1λλ′ = 1, in the algebrapairs6decades of spectrum18pairing error, general9.1·10⁻⁸pairing error, structured2.2·10⁻¹⁶a symmetry the solver never knew aboutand the half of the answer it decides

λ²A + λB + Aᵀ with A and B symmetric reads the same backwards, so λ is an eigenvalue exactly when 1/λ is. The axis is log₁₀|λ|, the marks are the computed eigenvalues and each arc joins a pair; the vertical line is |λ| = 1, about which the whole picture is symmetric. The spectrum spans 17.6 decades at b = 10⁸. Measured, the general solver's spectrum departs from being closed under λ ↦ 1/λ by 9.08·10⁻⁸, and the structured route's — one symmetric generalised eigenvalue problem of size 6 rather than an unsymmetric one of size 12 — by 2.16·10⁻¹⁶, which is the rounding level and is by construction.

logB: 6

The arguments are the ones A perturbation that keeps the symmetry passes. A value drawn at the generator's defaults instead would be a picture no essay asked for and no assertion has been run against.

The 12 eigenvalues of a palindromic quadratic, in 6 pairs whose products are oneλ²A + λB + Aᵀ with A and B symmetric reads the same backwards, so λ is an eigenvalue exactly when 1/λ is. The axis is log₁₀|λ|, the marks are the computed eigenvalues and each arc joins a pair; the vertical line is |λ| = 1, about which the whole picture is symmetric. The spectrum spans 13.6 decades at b = 10⁶. Measured, the general solver's spectrum departs from being closed under λ ↦ 1/λ by 6.56·10⁻⁸, and the structured route's — one symmetric generalised eigenvalue problem of size 6 rather than an unsymmetric one of size 12 — by 1.78·10⁻¹⁶, which is the rounding level and is by construction.-7-4.53944-2.078880.3816782.842245.30280log₁₀ |λ||λ| = 1λλ′ = 1, in the algebrapairs6decades of spectrum14pairing error, general6.6·10⁻⁸pairing error, structured1.8·10⁻¹⁶a symmetry the solver never knew aboutand the half of the answer it decides

λ²A + λB + Aᵀ with A and B symmetric reads the same backwards, so λ is an eigenvalue exactly when 1/λ is. The axis is log₁₀|λ|, the marks are the computed eigenvalues and each arc joins a pair; the vertical line is |λ| = 1, about which the whole picture is symmetric. The spectrum spans 13.6 decades at b = 10⁶. Measured, the general solver's spectrum departs from being closed under λ ↦ 1/λ by 6.56·10⁻⁸, and the structured route's — one symmetric generalised eigenvalue problem of size 6 rather than an unsymmetric one of size 12 — by 1.78·10⁻¹⁶, which is the rounding level and is by construction.

What it checked while drawing

Every figure above asserted its own claims on the way to being drawn, and a claim that failed would have failed the build rather than drawn a wrong picture. Those assertions used to leave no trace at all: a passing one returned true and the only evidence the figure had checked anything was that nothing crashed. The list below is what they actually said, collected by running this generator with an observer installed — not a description of what it is believed to check.

15 distinct claims across 6 sets of arguments, grouped below by shape — because most of them are one sentence with a different number in it, and how many separate times that sentence was put to the test is the informative part.

2n eigenvalues

a Cholesky factor of the second matrix, which requires it to be positive definite

a coupling for which both Cayley blocks are definite

a coupling the closed form can be read at

a linearisation has as many eigenvalues as it has rows

a reduction this file knows

a size the closed form can be read at

a spectrum that fits along the axis

a z that the Cayley map does not send to infinity

a z² that a real square root can be taken of

Jacobi needs a symmetric matrix

LU is for square matrices

matmul shapes agree

no eigenvalue at zero, which a palindromic problem cannot have

the structured route's spectrum is reciprocal

Against the rule

It draws a decomposition and prints its residual. It calls qepEigen, cayleyRoute, and every figure above carries the badge — which residualcheck verifies by looking for it in the emitted SVG rather than by finding the call that builds one. A badge that is constructed and then left out of the body is the failure that check exists for.

Across the library: the rule bites on 173 of 325 generators — 158 print a residual and 15 are exempt with a published reason; 152 factorise nothing. Read from lib/residual-rule.js, which is the same body the gate enforces from, and the gate's last check fails the build if this page and it disagree about any generator.

Where it is called

Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.

The eigenvalue problem that is not linear

A matrix that depends on its own eigenvalue

A damped structure does not produce Ax = λx. It produces (λ²M + λC + K)x = 0, where the matrix whose null vector is wanted is a function of the number being solved for — so there is nothing to factorise, an n × n problem has 2n answers, and the eigenvectors cannot be a basis.

Structure, and the solver that cannot see it

A perturbation that keeps the symmetry

The smallest perturbation that makes a computed answer exact is the backward error. Ask for the smallest one that also keeps the problem's structure and the number can only go up — and measured on a palindromic quadratic it goes up by 1.17, while the structure the computed spectrum has lost is not in either number.

The eigenvalue problem that is not linear

A problem with infinitely many eigenvalues

Let the matrix depend on λ through something that is not a polynomial and three things stop being true at once. There is no linearisation, there is no characteristic polynomial, and "compute the spectrum" is not a request that can be granted — the only finite question is how many eigenvalues are inside this circle.

The eigenvalue problem that is not linear

A spectrum that comes in reciprocal pairs

A palindromic quadratic reads the same backwards, so λ is an eigenvalue exactly when 1/λ is. A general solver discards that, computes the large half of the spectrum perfectly and the small half to seven digits — and the small half is a division away from being perfect too.

The eigenvalue problem that is not linear

Six routes to one spectrum

Three linearisations of one quadratic, each reduced to a standard eigenvalue problem two ways. All six have exactly the same eigenvalues in exact arithmetic. On a well-scaled problem they differ by noise; on a badly scaled one by a factor of forty; and two of the six are the same matrix.

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