Generator

σ ↦ σ(3 − σ²)/2, the map Newton–Schulz applies to every singular value, started at 1.6

One function in the polar library, called 2 times across 2 essays. Below: what it draws at its defaults, what it draws at every value an essay asks for, the 4 claims it put to the test while drawing them, and where it stands against the rule this site is named for.

At its defaults it draws σ ↦ σ(3 − σ²)/2, the map newton–schulz applies to every singular value, started at 1.6. The cubic and the diagonal, with the iteration from 1.6 drawn as a cobweb. The fixed points are 0, 1 and −1, and zero is repelling — its slope there is 3/2. Every starting value in (0, √3) is carried to 1, so the matrix iteration converges exactly when every singular value is inside that interval; √3 = 1.7320508 is sent to exactly zero, and past it the sequence leaves. From 1.6 the limit is 1.000000.

schulz-ball is one function in lib/figures/polar.js — the polar factor — the nearest orthogonal matrix, and two ways to it without an svd. Everything below came out of it during this build, at arguments taken from the essays rather than invented for this page. A figure here is the figure a reader meets in an essay, and if the generator changes, this page changes with it.

At its defaults

Drawn even though every essay passes arguments — which on this site is every essay, at 100% of placements since the standard pass. A default nothing exercises is a trap for the next essay to call this with none, and this is the page where a default that has drifted from the figures around it becomes visible.

σ ↦ σ(3 − σ²)/2, the map Newton–Schulz applies to every singular value, started at 1.6The cubic and the diagonal, with the iteration from 1.6 drawn as a cobweb. The fixed points are 0, 1 and −1, and zero is repelling — its slope there is 3/2. Every starting value in (0, √3) is carried to 1, so the matrix iteration converges exactly when every singular value is inside that interval; √3 = 1.7320508 is sent to exactly zero, and past it the sequence leaves. From 1.6 the limit is 1.000000.the whole convergence theory of an n×n iteration is this cubic√3start 1.610−1fixed points 0, 1, −1start1.6after one step0.35limit1the boundary, √31.7outside the basin it still convergesto an orthogonal matrix that is not the answer

The cubic and the diagonal, with the iteration from 1.6 drawn as a cobweb. The fixed points are 0, 1 and −1, and zero is repelling — its slope there is 3/2. Every starting value in (0, √3) is carried to 1, so the matrix iteration converges exactly when every singular value is inside that interval; √3 = 1.7320508 is sent to exactly zero, and past it the sequence leaves. From 1.6 the limit is 1.000000.

alpha: 2.24

The arguments are the ones An answer that changes with the seed passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

σ ↦ σ(3 − σ²)/2, the map Newton–Schulz applies to every singular value, started at 2.24The cubic and the diagonal, with the iteration from 2.24 drawn as a cobweb. The fixed points are 0, 1 and −1, and zero is repelling — its slope there is 3/2. Every starting value in (0, √3) is carried to 1, so the matrix iteration converges exactly when every singular value is inside that interval; √3 = 1.7320508 is sent to exactly zero, and past it the sequence leaves. From 2.24 the limit is not finite.the whole convergence theory of an n×n iteration is this cubic√3start 2.2410−1fixed points 0, 1, −1start2.2after one step-2.3limit10³⁰⁸the boundary, √31.7outside the basin it still convergesto an orthogonal matrix that is not the answer

The cubic and the diagonal, with the iteration from 2.24 drawn as a cobweb. The fixed points are 0, 1 and −1, and zero is repelling — its slope there is 3/2. Every starting value in (0, √3) is carried to 1, so the matrix iteration converges exactly when every singular value is inside that interval; √3 = 1.7320508 is sent to exactly zero, and past it the sequence leaves. From 2.24 the limit is not finite.

alpha: 1.6

The arguments are the ones The nearest orthogonal matrix passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.

σ ↦ σ(3 − σ²)/2, the map Newton–Schulz applies to every singular value, started at 1.6The cubic and the diagonal, with the iteration from 1.6 drawn as a cobweb. The fixed points are 0, 1 and −1, and zero is repelling — its slope there is 3/2. Every starting value in (0, √3) is carried to 1, so the matrix iteration converges exactly when every singular value is inside that interval; √3 = 1.7320508 is sent to exactly zero, and past it the sequence leaves. From 1.6 the limit is 1.000000.the whole convergence theory of an n×n iteration is this cubic√3start 1.610−1fixed points 0, 1, −1start1.6after one step0.35limit1the boundary, √31.7outside the basin it still convergesto an orthogonal matrix that is not the answer

The cubic and the diagonal, with the iteration from 1.6 drawn as a cobweb. The fixed points are 0, 1 and −1, and zero is repelling — its slope there is 3/2. Every starting value in (0, √3) is carried to 1, so the matrix iteration converges exactly when every singular value is inside that interval; √3 = 1.7320508 is sent to exactly zero, and past it the sequence leaves. From 1.6 the limit is 1.000000.

What it checked while drawing

Every figure above checked its own claims on the way to being drawn, and a claim that failed would have stopped the picture rather than shipped a wrong one. Those checks used to leave no trace at all: a passing one returned true and the only evidence the figure had checked anything was that nothing crashed. The list below is what they actually said, collected by running this generator with an observer installed — not a description of what it is believed to check.

4 distinct claims across 3 sets of arguments, grouped below by shape — because most of them are one sentence with a different number in it, and how many separate times that sentence was put to the test is the informative part.

a starting value the cubic keeps finite for a few steps

and every starting value above it goes somewhere else

and every starting value below √3 is carried to one

the cubic sends √3 to exactly zero

Against the rule

The rule does not apply to it. It factorises nothing, so there is no residual it could be withholding. That is worth stating rather than leaving blank: a site that reported the rule as satisfied by every generator would be counting mostly generators the rule never reached.

Across the library: the rule bites on 217 of 397 generators — 199 print a residual and 18 are exempt with a published reason; 180 factorise nothing. Read from lib/residual-rule.js, which is the same body the gate enforces from, and the gate's last check fails the build if this page and it disagree about any generator.

Where it is called

Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.

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