The widths a proof is available at, against the precision
At its defaults it draws the widths a proof is available at, against the precision. Two boundaries against the number of significand bits, on a logarithmic vertical axis, with the band between them shaded. The narrow boundary runs from 0.00162 at 12 bits to 3.33·10⁻¹⁶ at 53, a small multiple of u at each. The wide boundary is 1.414214 at every precision — which is √2, the half-width at which the box first touches the line where the Jacobian is singular.
verification-band is one function in lib/figures/krawczyk.js —
verdicts — exactly one root in this box, or none, or nothing can be said. Everything below came out of it during this build, at
arguments taken from the essays rather than invented for this page. A figure here is the
figure a reader meets in an essay, and if the generator changes, this page changes with it.
At its defaults
Drawn even though every essay passes arguments — which on this site is every essay, at 100% of placements since the standard pass. A default nothing exercises is a trap for the next essay to call this with none, and this is the page where a default that has drifted from the figures around it becomes visible.
Two boundaries against the number of significand bits, on a logarithmic vertical axis, with the band between them shaded. The narrow boundary runs from 0.00162 at 12 bits to 3.33·10⁻¹⁶ at 53, a small multiple of u at each. The wide boundary is 1.414214 at every precision — which is √2, the half-width at which the box first touches the line where the Jacobian is singular.
precisions: [12, 16, 20, 24, 32, 53]
The arguments are the ones Proving the answer is in the box passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
Two boundaries against the number of significand bits, on a logarithmic vertical axis, with the band between them shaded. The narrow boundary runs from 0.00162 at 12 bits to 3.33·10⁻¹⁶ at 53, a small multiple of u at each. The wide boundary is 1.414214 at every precision — which is √2, the half-width at which the box first touches the line where the Jacobian is singular.
What it checked while drawing
Every figure above checked its own claims on the way to being drawn, and a claim that failed
would have stopped the picture rather than shipped a wrong one. Those checks used to leave
no trace at all: a passing one returned true and the only evidence the figure had
checked anything was that nothing crashed. The list below is what they actually said, collected
by running this generator with an observer installed — not a description of
what it is believed to check.
16 distinct claims across 2 sets of arguments, grouped below by shape — because most of them are one sentence with a different number in it, and how many separate times that sentence was put to the test is the informative part.
the narrow boundary is a small multiple of u at 12 bits — checked 6 times
and falls with the precision at 16 bits — checked 5 times
a precision the arithmetic can round outward at
and is √2 — the distance to the singular Jacobian
enough precisions to show the trend
LU is for square matrices
while the wide boundary barely moves
Against the rule
The rule does not apply to it. It factorises nothing, so there is no residual it could be withholding. That is worth stating rather than leaving blank: a site that reported the rule as satisfied by every generator would be counting mostly generators the rule never reached.
Across the library: the rule bites on 217
of 397 generators —
199 print a residual and
18 are exempt with a published reason;
180 factorise nothing.
Read from lib/residual-rule.js, which is the same body the gate enforces from,
and the gate's last check fails the build if this page and it disagree about any generator.
Where it is called
Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.
Proving the answer is in the box
Every other method here computes a number and estimates how wrong it is. This one returns a verdict: there is exactly one solution in this box, or there is none, or — the honest third outcome — nothing can be said. Two of the three are proofs about infinitely many points from finitely many operations.
The arithmetic underneathThe numbers below the smallest one
Below the smallest normal number the spacing stops halving and stays put, all the way to zero. That is what gradual underflow is, and the thing it buys is the sentence every algorithm assumes without being told — x minus y is zero only when x equals y.