The optimal upwinding parameter, and the two schemes it contains
At its defaults it draws the optimal upwinding parameter, and the two schemes it contains. ξ = coth(Pe) − 1/Pe against the cell Péclet number on a logarithmic horizontal axis. It runs from zero to one: at small Pe it behaves like Pe/3, so the added diffusion vanishes faster than the grid and the scheme becomes central differencing; at large Pe it approaches one — 0.9667 at Pe = 30 — where the added diffusion is h/2 and the scheme becomes upwinding.
xi-curve is one function in lib/figures/supg.js —
tuned diffusion — exact at the nodes, on the problem it was derived from. Everything below came out of it during this build, at
arguments taken from the essays rather than invented for this page. A figure here is the
figure a reader meets in an essay, and if the generator changes, this page changes with it.
At its defaults
Drawn even though every essay passes arguments — which on this site is every essay, at 100% of placements since the standard pass. A default nothing exercises is a trap for the next essay to call this with none, and this is the page where a default that has drifted from the figures around it becomes visible.
ξ = coth(Pe) − 1/Pe against the cell Péclet number on a logarithmic horizontal axis. It runs from zero to one: at small Pe it behaves like Pe/3, so the added diffusion vanishes faster than the grid and the scheme becomes central differencing; at large Pe it approaches one — 0.9667 at Pe = 30 — where the added diffusion is h/2 and the scheme becomes upwinding.
hiPe: 100
The arguments are the ones A parameter that is also a price passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
ξ = coth(Pe) − 1/Pe against the cell Péclet number on a logarithmic horizontal axis. It runs from zero to one: at small Pe it behaves like Pe/3, so the added diffusion vanishes faster than the grid and the scheme becomes central differencing; at large Pe it approaches one — 0.9900 at Pe = 100 — where the added diffusion is h/2 and the scheme becomes upwinding.
hiPe: 30
The arguments are the ones The diffusion that makes the answer exact passes. A value nobody placed would be a picture no essay asked for and no claim was ever checked against.
ξ = coth(Pe) − 1/Pe against the cell Péclet number on a logarithmic horizontal axis. It runs from zero to one: at small Pe it behaves like Pe/3, so the added diffusion vanishes faster than the grid and the scheme becomes central differencing; at large Pe it approaches one — 0.9667 at Pe = 30 — where the added diffusion is h/2 and the scheme becomes upwinding.
What it checked while drawing
Every figure above checked its own claims on the way to being drawn, and a claim that failed
would have stopped the picture rather than shipped a wrong one. Those checks used to leave
no trace at all: a passing one returned true and the only evidence the figure had
checked anything was that nothing crashed. The list below is what they actually said, collected
by running this generator with an observer installed — not a description of
what it is believed to check.
3 distinct claims across 3 sets of arguments, grouped below by shape — because most of them are one sentence with a different number in it, and how many separate times that sentence was put to the test is the informative part.
a Péclet range the limit is visible in
and behaves like Pe/3 at the small end
ξ approaches one like 1/Pe
Against the rule
The rule does not apply to it. It factorises nothing, so there is no residual it could be withholding. That is worth stating rather than leaving blank: a site that reported the rule as satisfied by every generator would be counting mostly generators the rule never reached.
Across the library: the rule bites on 217
of 397 generators —
199 print a residual and
18 are exempt with a published reason;
180 factorise nothing.
Read from lib/residual-rule.js, which is the same body the gate enforces from,
and the gate's last check fails the build if this page and it disagree about any generator.
Where it is called
Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.
A parameter that is also a price
ξ = coth(Pe) − 1/Pe is the fraction of h/2 that makes a boundary-layer solution exact at every node. On a problem with no layer in it, the error the same scheme commits is ξ times upwinding's — 0.2511 against a ξ of 0.2504, 0.7461 against 0.7448 — so the number that buys the exactness is also the invoice.
Iterating, instead of factorisingThe diffusion that makes the answer exact
Upwinding adds h/2 of artificial diffusion. Central differencing adds none. Add ε·ξ·Pe with ξ = coth(Pe) − 1/Pe and the computed solution is the exact one at every grid point, to 2.4·10⁻¹⁷ — at every Péclet number, on the problem it was derived from and on no other.