Sparse pivoting — the series
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Structure and stability stop being separable
The sparsest variable to eliminate on this matrix has a diagonal entry of 10⁻¹². Eliminating it produces the smaller factor, reproduces the matrix to 3.8·10⁻¹⁷ — better than pivoting does — and returns an answer wrong in the fifth digit.
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A threshold between fill and growth
One number decides how small a pivot an elimination will accept. At 0.001 the factor holds 172 entries and the matrix grows by 1,330; at 1 it holds 260 and grows by 1.2. The libraries ship 0.1, and the measurement says why.
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What the symbolic phase can only bound
Without pivoting, the fill can be computed from the graph and the count is exact — 233 predicted, 233 measured. With pivoting it is 233 predicted and 242 measured, and what survives is a bound that is right at every threshold and loose by 1.7 times at the largest grid drawn.
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The order that was right last time
A pivot order computed once and reused across a sequence saves the symbolic phase, and the price is that a pivot which was large may now be small. Replacing it with √u·‖A‖ costs eight orders of backward error and iterative refinement recovers a factor of 8.8 of them. Divide each row by its largest entry first and the same reuse costs nothing at all.
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An ordering that does not wait for the numbers
A sparse factorisation's memory is decided by an ordering computed from the graph, and its stability by pivots computed from the values, and the two decisions fight. On one family of matrices they do not — the ordering can be chosen for fill alone, and the fill the symbolic phase predicts is the fill the factorisation produces — exactly, not as a bound.
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The column that was never fixed
Every threshold-pivoting measurement so far chose the pivot row in a fixed column, and the routine's own description said that choosing the column as well would change the constants and not the argument. Measured, it changes the argument. On the 8×8 conflict grid the factor shrinks from 875 entries to 640 at the library default, and the growth factor that climbed to 2,209 as the threshold loosened stays at 2.54 at every threshold from 0.3 down to 0.001. What does most of the work is not the column but which of several equally cheap entries is taken — and on random sparse matrices, choosing the column without that makes the growth worse.
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How few columns the search needs
A full row-and-column pivot search is quadratic in the active submatrix at every step, and no library performs one. Looking at a single sparsest column takes the median fill from 244 to 136 where the full search reaches 109 — four fifths of the benefit for a linear scan — and that share is 79, 83, 80, 89 and 92 per cent across five thresholds. The worst growth appears to favour the narrow search by a factor of six, and on the next draw it favours the wide one by two.
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The freedom a symmetric factorisation does not have
Permuting rows and columns together leaves no column to choose, so the conflict between the sparsest pivot and the sound one should be worse rather than better. On a saddle-point matrix whose constraint rows have no diagonal entry at all, it is not there: taking the sparsest available pivot holds 70 entries against the natural order's 113 and a growth of 1.28 against 1.83 — better on both currencies at once, at every setting of the pivot test. The two-by-two blocks that make it legal cost 1.33 entries apiece.
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An order fixed before the numbers
On a saddle-point matrix whose constraint rows have no diagonal, taking the sparsest pivot at every step beat the natural order on fill and growth at once, and the reading was deferral: the constraint rows go last and have filled in by then. A code computes its ordering once, from the pattern. That static minimum-degree order holds fewer entries than re-reading the degrees on fourteen of sixteen settings, growth under two throughout — and it does not defer. It spreads the constraint rows through the elimination, each after two thirds of its own variables. Scatter small pivots through a grid instead and the plan is refused on up to 25 of 64 steps; its saving falls from 31 per cent to 3.
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A plan redrawn where it was refused
A symmetric indefinite factorisation planned once from the pattern loses its fill saving as small pivots are scattered through the diagonal — on an 8 × 8 grid it keeps 74 per cent of what re-reading the degrees at every step saves at one small pivot in twenty, and 20 per cent at three in ten. Redraw the plan for the remaining rows only when the pivoting criterion rejects the planned pivot, and it keeps 85 to 100 per cent at every share up to three in ten, reading a tenth to a quarter of the rows the step-by-step rule reads. Each redrawn plan heads off refusals that would have followed it: 3 re-plans where the fixed plan was refused 7 times, 9 where it was refused 17. Where the plan was never refused, redrawing costs nothing — and with half the diagonal small, no plan of any kind beats the natural order.
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A small pivot with a small neighbour
A fill-reducing plan computed from the pattern loses its saving as small pivots are scattered through a symmetric indefinite matrix, and redrawing it where the pivoting test refuses it wins the saving back. Gather the same small pivots into one region and the prediction was that the fixed plan would do worse, because a whole region's ranking is wrong at once. It does better. On 8 × 8 and 10 × 10 grids the fixed plan is refused 0 to 6 times with the small pivots clustered, against 7 to 19 scattered, and at three in ten it saves 10 and 23 per cent of the natural order's factor where scattered it saved 3 and 9. The reason is in the Bunch–Kaufman test: a small pivot whose neighbour is also small cannot be passed over for that neighbour, so the test pairs the two into a block that keeps the planned row. Both plans still save something with half the diagonal small. And the step-by-step sparsest rule, best of all when the small pivots are scattered, falls behind the redrawn plan in a cluster.
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A refusal has no fixed price
A symmetric indefinite factorisation planned once from the pattern is refused by its pivoting test where small diagonal entries sit, and the earlier essays read the refusal count as the plan's cost: scattered small pivots were refused 7 to 19 times and saved little, clustered ones 0 to 6 and saved much more. Put the small pivots along lines, each with two small neighbours, and the prediction of one refusal for every three small entries holds — between 0.25 and 0.42 on every share and grid. The rest of the reading does not. From a fifth of the diagonal up, the three layouts add within a factor of 1.6 of the same number of entries to the fixed plan's factor while their refusal counts differ by three to seven times. What moved the earlier savings was the baseline: the natural order's factor changes with the layout too, by 13 per cent at three in ten, and on the 10 × 10 grid the lines 'save' 19 per cent where the scatter saves 9 — with fixed-plan factors of 907 and 898 entries.
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The baseline was the interchanges
Small pivots along grid rows gave a fixed fill-reducing plan twice the saving over the natural order that scattered ones did, for a factor of the same size, and the reading was that the natural order did badly on rows. Turning the lines to run along columns was predicted to bring the natural order below 1,000 entries, leave the plan within 3 per cent of 907, and drop the saving to the scatter's. It misses on all three: 1,008, 977 and 3.1 per cent. What the natural order paid for on rows was its own interchanges. Offered by position, as a dense code offers it, every Bunch–Kaufman interchange moves a row out of sequence, and on rows that costs 125 entries at three in ten and 191 at half — the most of any layout at every share. Kept to the grid's index, the natural order barely notices the layout, and the row lines' saving halves to 9.0 per cent.