Numerical Linear Algebra
where the algebra stops being the arithmetic
Concept

Catastrophic cancellation — where it appears

4 essays name this object, across 2 fields. What follows is each of them, and the objects they name alongside it.
10⁻¹²10⁻¹⁰10⁻⁸10⁻⁶10⁻⁴10⁻²110⁻¹⁷10⁻¹⁴10⁻¹¹10⁻⁸10⁻⁵10⁻²10¹xrelative error of the computed value(1 − cos x)/x², as written2 sin²(x/2)/x²no digits left at allbinary64 throughoutone function, two spellings · zero below 1.5·10⁻⁸

Cancellation takes the answer, not a digit

Subtracting two nearly equal numbers is exact. That is what makes it dangerous — the subtraction introduces no error at all, it exposes error the operands were already carrying, and the exposure can consume every significant figure at once.

arithmetic · cancellation the mirrorx, length 4.000Hx = (-4.000, 0)v = x − αe₁safe sign: α = −‖x‖, so v is formed from a sum and nothing cancelsunsafe sign: α = +‖x‖ gives ‖v‖ only 35.1% of ‖x‖ + ‖x‖ — the digits go‖HᵀH − I‖5·10⁻¹⁶‖Hx‖ − ‖x‖8.9·10⁻¹⁶second component2.2·10⁻¹⁶built from a unit vectororthogonality is structural

A reflection cannot stop being one

Householder QR holds orthogonality at 10⁻¹⁵ whatever the condition number of the matrix, and Gram–Schmidt does not. The reason is not that it is more careful. It is that its Q is built from unit vectors, and rounding a unit vector gives a different reflection rather than a broken one.

orthogonality · householder 012345610⁻¹⁶10⁻¹³10⁻¹⁰10⁻⁷10⁻⁴10⁻¹refinement step‖x − x*‖ / ‖x*‖a full double-precision solveresidual in24-bitresidual indoubleone argument apartκ·u of the factorisation6·10⁻⁴double residual, final3.2·10⁻¹³same-precision, final1.3·10⁻⁴30×30, κ = 10⁴, same factors in both runsidentical cost

Buying the accuracy back

Factorise in single precision, then correct the answer using residuals computed in double, and the result is what a full double-precision solve would have given. Compute those residuals in single instead and the identical algorithm, at identical cost, recovers nothing.

arithmetic · mixed precision -47-37-27-17-7313233301234log₁₀ of the vector's normfp1611 bitsbfloat168 bitstf3211 bitsbinary3224 bitspale: the format's range · blue: √(Σ(xᵢ/m)²)·m · red: √(Σxᵢ²)fp16 and tf32 have the same eleven significand bitsand their bars do not overlap

A norm that overflows before it is a norm

The vector of sixteen thousands has a Euclidean norm of 4,000, which fp16 represents exactly. Written as the square root of the sum of squares it returns infinity, because squaring doubles the exponent — and the expression costs half the format's range on the one computation every iterative method performs at every step.

arithmetic · overflow

Named alongside it

The objects these essays reach for when they reach for this one.

Gaussian eliminationBackward errorbfloat16Dynamic rangeForward errorGram–SchmidtHalf precisionHouseholder reflectionhypotIterative refinementJacobi's eigenvalue methodMixed precision

All concepts