Concept

Error accumulation — where it appears

The growth of a computation's error as it performs more operations. Whether it grows like the number of steps or like the square root of it depends on whether the individual errors share a direction, and this site measures both cases.

Named by 15 essays across 6 fields — each of them below, with the objects they name alongside it.

110¹10⁻¹¹10⁻⁸10⁻⁵pieces the vector was divided intodistance from the exact sum, relativethe published boundκ · uone vector, one algorithmdistinct answers21runs26spread, in ulps2.3·10⁷κ of the sum10⁸bound ÷ worst error2.6·10⁴nobody chose pand no answer is the answer

The same program, twice

One vector of 4,096 numbers, one summation algorithm, one precision, twenty-six runs — and twenty-one different answers. Nothing in the program chose between them, every one of them satisfies the textbook bound, and the exactly rounded answer is not among them.

machine · Reduction order
[½, 1)[1, 2)[2, 4)0.5124gap 0.125gap 0.25 — twice as wide8 values per octavespacing doubles at each power of two

What a float can hold

The representable numbers are not a fine fuzz spread evenly over the line. They are evenly spaced inside each power-of-two interval and twice as far apart in the next one up, and almost everything else in this subject is a consequence of that one fact.

arithmetic · Floating-point
10⁻⁸10⁻⁷10⁻⁶10⁻⁵10⁻⁴10⁻³10⁻²10⁻¹10⁻⁹10⁻⁷10⁻⁵10⁻³10⁻¹10¹ε in Läuchli's matrix (smaller ε, larger κ)relative error in the coefficientsAᵀA exactly singularnormal equationsQRκ from 1.7·10⁸ to 17the cliff is at √u = 2.4·10⁻⁴

The road that squares the problem

The normal equations are the first method every course teaches and the method no library uses. Forming AᵀA squares the condition number, and below ε = √u it does not degrade — it produces a matrix that is exactly singular, from data that was perfectly usable.

leastsquares · Normal equations
10²10⁴10⁶10⁸10¹⁰10¹²10⁻¹⁷10⁻¹⁴10⁻¹¹10⁻⁸10⁻⁵10⁻²10¹κ of the sumrelative sizethe boundκ · umeasured spreadtwo curves and one constantspread ÷ κu, low0.25spread ÷ κu, high0.26bound ÷ spread, low7932decades swept10the spread is computablethe bound cannot see the order

A bound every answer satisfies

The classical bound on a summation error is correct, it covers all twenty-six answers one vector produced, and it is 7,932 times larger than the difference between them. A statement true of every ordering cannot say which ordering you got.

machine · Reduction order
051210241536204810⁻¹⁷10⁻¹⁴terms consumederror accumulated so farone accumulator8 piecesthe steps are the partial sumspeak partial sum32the answer1.6·10⁻⁵error, one piece7.6·10⁻¹⁴error, 8 pieces2.4·10⁻¹⁴mean at p = 648.1·10⁻¹⁵the walk sets the sizeand nothing sets the value

Where the disagreement comes from

The error of a reduction is a walk whose step length is the spacing of the running total, not of the answer. That one sentence predicts the size of the disagreement to a factor of two, explains why dividing the work makes it smaller, and explains why the value cannot be predicted at all.

machine · Reduction order
10¹10²10³10⁴10⁵10⁶10⁻⁹10⁻⁷10⁻⁵10⁻³10⁻¹number of terms addedrelative error against the exact sumin orderin a treecompensatedbinary32 · terms are 1/icompensated: 3·10⁻⁸

The order they are added in

Addition is associative in the algebra and is not associative in the arithmetic. The same million numbers, added in a different order, give answers that differ in the third significant figure — and the fix is not a wider float, it is a different order.

arithmetic · Summation
-0.16-0.63-0.493.43-0.025-0.632.3-0.69-0.95-1.70.076-0.49-0.694.3-1.6-1.41.93.4-0.95-1.65.40.0141.63-1.7-1.40.0144.60.055-0.0250.0761.91.60.0553.1A, symmetric→-0.164.600004.65.92.500002.51-1.20000-1.24.90.3800000.385.80.2400000.242H = QᵀAQ, tridiagonal‖A − QHQᵀ‖/‖A‖1.1·10⁻¹⁵below the subdiagonal0worst eigenvalue movement7.1·10⁻¹⁵a similarity, so the spectrum is untouched — and every later step is O(n²) rather than O(n³)one reduction, then every iteration is cheapthe eigenvalues did not move

The form that makes it affordable

One Householder reduction, done once, turns every subsequent iteration of the eigenvalue algorithm from cubic to quadratic cost. It changes no answer at all, which is why it is easy to describe as an optimisation and wrong to.

spectra · The QR algorithm
0816243211.11.21.31.4terms added, each followed by a truncationerror ⁄ best rank-k erroroptimalterms with nothing in commona subspace that driftsthe rounding nobody should have feareddrifting, worst excess1independent, worst excess1a linear bound would say32energy discarded, first1.8·10⁻⁷energy discarded, last0.03thirty-two roundingsand four per cent

The rounding that was not the problem

A rank-k block plus a rank-k block is a rank-2k block, exactly, so every arithmetic in this format truncates after every addition. A Cholesky performed inside it does ninety-eight of those and its residual is 1.14·10⁻⁹ against a representation error of 1.40·10⁻⁹ — the roundings cost nothing measurable.

hierarchy · Recompression
10²10³10⁴10⁻⁸10⁻⁷10⁻⁶10⁻⁵10⁻⁴terms summedrelative error+∞, −∞ 1.01zero 1.00stochastic 0.50nearest 0.47√n against n, fittednearest, fitted exponent0.47stochastic, fitted exponent0.5toward +∞, fitted exponent1twelve seeds averaged at each sizethe slope is the bias, not the precision

The direction the error leans

The size of one rounding error is set by the precision. How ten thousand of them combine is set by something else entirely — the rounding mode — and the fitted exponents are 0.47 for round-to-nearest and 1.01 for round-toward-infinity, on identical data at identical precision.

arithmetic · Rounding
-101-101(x − 1) ÷ 0.001p(x) ÷ 2.68·10⁻¹⁵a square, drawn negativepoints sampled401negative, unfused179negative, fused196signs disagree at98widest gap1.4·10⁻¹⁵unfusedfusedthe true valuethe true curve is the flat oneeverything else is rounding

A square that evaluates negative

(x − 1)⁶ evaluated near x = 1 comes out negative at 179 of 401 points on one build and 196 on another, and the two disagree about the sign at 98 of them. Neither is nearer the truth: both traces are made entirely of rounding.

machine · Fma contraction
02505007501000250275300325350375additionsrunning totalround to nearest: nothing arrivesexactstochasticnearesta thousand additionshalf an ulp at 2561moves, round to nearest0moves, stochastic46relative error, nearest0.28relative error, stochastic0.0228 significand bits, unbounded exponenta flat line is not a small error

A coin flip that fixes the average

Add 0.1 to 256 a thousand times at eight significand bits and the answer is 256. Not approximately — the total never moves, not once, and no error bound says so. Round up one time in twenty instead of never, and it arrives at 348 against a true 356.

arithmetic · Rounding
02040608010010⁻¹¹10⁻¹⁰10⁻⁹10⁻⁸truncations performed by the factorisationrelative errorthe representation's own error‖A − LLᵀ‖ ⁄ ‖A‖no decomposition without its residualresidual, 0 truncations2.1·10⁻¹⁰residual, 98 truncations1.1·10⁻⁹representation, deepest1.4·10⁻⁹residual ⁄ representation0.81levels, deepest5a hundred approximate stepsand an exact-looking factorisation

The count that is not the budget

A Cholesky performed inside a low-rank format truncates 0, 2, 10, 34 and 98 times as the leaf falls from 128 to 8, and those five integers are the same at every accuracy from 10⁻¹² to 10⁻². Across all ten decades the factorisation's residual stays below the representation's own error at a ratio between 0.81 and 1.00 — with two entries that read 1.83 and 1.78, and neither of them is accumulation.

hierarchy · Recompression
5860626466687010⁻¹⁷10⁻¹⁶terms in the dot productmean relative errorthe kernel changes herea constant in a libraryone accumulator3.2·10⁻¹⁷four accumulators2.1·10⁻¹⁷step at the cutoff1.6cutoff64the problem did not changethe loop did

The length that changes the kernel

A dot product's accuracy steps by a factor of 1.57 between 63 and 64 terms, on vectors drawn identically at both lengths. Nothing about the problem changes there. A library switches from one accumulator to four, at a constant in somebody else's source file.

machine · Algorithm selection
01020304050607010⁻⁶10⁻³110³10⁶10⁹k‖Aᵏ/k!‖‖e^A‖ = 2.6largest term 1.4·10⁷what the series throws awaylargest term1.4·10⁷‖e^A‖2.6digits cancelled away5.4·10⁶error after the sum5.2·10⁻⁹every term is computed correctlyand the sum has lost seven digits

The error the method already knows

Summing the exponential's Taylor series throws away a known number of digits, and the number is on the machine while the sum is being formed. The largest term divided by the answer, times the unit roundoff, tracks the relative error that comes out — to within a factor of nine, across fourteen orders of magnitude of it — and nothing reports it.

spectra · Matrix function
10³10⁶10⁹10¹²10¹⁵10⁻¹⁵10⁻¹²10⁻⁹10⁻⁶10⁻³1largest iterate on the way, ‖x‖difference between the two residualsthe bound, linear in ‖x‖what it does, slope 0.46a bound of one, a walk of a halffitted slope0.46the bound's slope1smallest gap measured3.9·10⁻¹⁵largest gap measured1.5·10⁻¹⁰share of the bound, near end9.1·10⁻⁴share of the bound, far end3.4·10⁻⁹the bound is rightand loose by a square root

A walk needs a length

The gap between the two residuals grows as the square root of something, and a square root needs a length. Two quantities are candidates — how far the iterates travelled and how many steps were taken — and only a second sweep separates them. Across a fourfold change in size the iteration count goes from 39 to 96 and the gap goes from 5.04·10⁻¹⁵ to 5.33·10⁻¹⁵.

iterative · Residual gap

Named alongside it

The objects these essays reach for when they reach for this one.

Unit roundoffReduction orderRun-to-run variationRandom walkResidualSummationSummation condition numberAssociativityBitwise reproducibilityCatastrophic cancellationCholesky factorisationEckart–Young

All concepts