Concept

Fraction-free elimination — where it appears

Gaussian elimination over the integers in which each step divides by the previous pivot, a division that is exact at every step of every matrix. Every intermediate it forms is a minor of the original matrix, which bounds the length of the numbers by Hadamard's inequality rather than letting it double per step.

Named by 4 essays across one field — each of them below, with the objects they name alongside it.

3456789101112110¹10²10³10⁴10⁵10⁶nwidest intermediate, in bitsrationals, not reducedfraction-free · rationals reduced · the answerone answer, three widthsn12answer40Hadamard bound52fraction-free40reduced rationals39unreduced1.4·10⁶the error is zero on every curvethe cost is the length of the numbers

An answer with no error in it

An integer matrix eliminated over the rationals rounds nothing, so the forward error is zero, the residual is the zero vector, and the identity this site is built on has no terms left. The cost does not vanish with the error. It moves into the length of the numbers, where three correct routes differ by four orders of magnitude.

exact · Exact cost
1-2-6-7-474-26-12-5-8-524-394151435A, the matrix as given1-2-6-7-401840552700112217207003943011710017279153after 2 fraction-free steps3 × 3 minors25 divisions, all exactthe intermediates are minorswhich is why the divisions come out whole

Every intermediate is a minor

Fraction-free elimination divides by the previous pivot at every step and the division is always exact. Not usually, not for these entries — always, because the number being divided is a determinant with that pivot as a factor, which is a theorem and is checked here against the minors themselves.

exact · Fraction-free
3456789101110²10³nbitsthe answerthe question · det Abits in, bits outn11question484answer729det A33widest part37the answer is the floorand no route writes it down more cheaply

The answer is longer than the question

An exact solution of an integer system is a vector of fractions, each of them a ratio of two determinants. So the output carries 2n long integers where the input carried n² short ones, and no algorithm can write it down more cheaply — the length of the answer is a floor under every exact solver rather than a property of one.

exact · Exact cost
34567891011110¹10²nbitsthe budget and what it buysrandom, bound47random, actual33primes needed2Hadamard n = 8, bound13Hadamard n = 8, actual13the count is decided by a theorembefore any arithmetic happens

How many primes the answer needs

Work modulo a word-sized prime and no intermediate can exceed twenty-six bits, whatever the matrix does. The catch is that the answer must be reassembled from several such computations, and the number of them has to be fixed before the first one runs — by a theorem about how large a determinant can be, not by trying more until it settles.

exact · Modular lift

Named alongside it

The objects these essays reach for when they reach for this one.

Bit lengthExact arithmeticHadamard boundDeterminantBackward errorChinese remainder theoremCondition numberCramers ruleExact ground truthIntermediate expression swellMinorModular arithmetic

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