Chinese remainder theorem — where it appears
Named by 3 essays across one field — each of them below, with the objects they name alongside it.
How many primes the answer needs
Work modulo a word-sized prime and no intermediate can exceed twenty-six bits, whatever the matrix does. The catch is that the answer must be reassembled from several such computations, and the number of them has to be fixed before the first one runs — by a theorem about how large a determinant can be, not by trying more until it settles.
A prime that divides the answer
A modular elimination reports a singular matrix and is telling the truth — over the field with p elements the matrix is singular. Over the rationals it is not. Nothing in the residue distinguishes the two cases, no quantity is small enough to be suspicious, and the wrong answer is a correct computation of a different question.
A fraction recovered from one remainder
A solution over the rationals can be computed modulo a prime power and then recovered — the residue determines the fraction uniquely, but only once the modulus is twice the square of the fraction's longer part. Below that there is no partial credit: the algorithm returns a different fraction with the same residue, and it is a perfectly good one.
Named alongside it
The objects these essays reach for when they reach for this one.
Exact arithmeticModular arithmeticBit lengthDeterminantHadamard boundCramers ruleFraction-free eliminationLatticeRank is a decisionRational reconstructionUnlucky prime