Residual replacement — where it appears
Named by 2 essays across one field — each of them below, with the objects they name alongside it.
The residual the method reports
Conjugate gradients prints a relative residual of 6.9·10⁻²¹. The unit roundoff is 1.1·10⁻¹⁶, so that is not a small residual and not a large one — it is not a residual. The vector the method is holding at that step has ‖b − Ax‖/‖b‖ = 5.1·10⁻¹⁰, and nothing in the run says so.
A walk needs a length
The gap between the two residuals grows as the square root of something, and a square root needs a length. Two quantities are candidates — how far the iterates travelled and how many steps were taken — and only a second sweep separates them. Across a fourfold change in size the iteration count goes from 39 to 96 and the gap goes from 5.04·10⁻¹⁵ to 5.33·10⁻¹⁵.
Named alongside it
The objects these essays reach for when they reach for this one.
Condition numberConjugate gradientsKrylov subspaceRandom walkStopping criterionUnit roundoffBackward errorCancellationError accumulation